Question

A line contains the points (1, –6) and (–2, 6). What is the slope of a line that is perpendicular to this line?

Answer 1

First, find the slope of the line contains the points (1,-6) and (-2,6) using slope formula
m = $\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

plug in the numbers
m = $\dfrac{6-(-6)}{-2-1}$
m = $\dfrac{6+6}{-3}$
m = $\dfrac{12}{-3}$
m = -4

Second, determine the slope of perpendicular line
The slope of the perpendicular line is the opposite and reciprocal from the other line. Thus, the slope is $\dfrac{1}{4}$