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hichkok12 [17]
3 years ago
13

Im in dyer need of how to solve these problems

Mathematics
1 answer:
melisa1 [442]3 years ago
5 0
#4)
{ A}
Triangle ABC is congruent to triangle YXZ. How do I know this?
 Look at the angles and adjacent (bottom) line.
Because Angle A and Angle Y are both equal to (what I believe says) 78 degrees, they are equal. 
Next, Angle B is equal to Angle X because it is the angle that connects the adjacent (bottom) line and the hypotenuse (top line). Even though they have no measurements or tick marks, it's the process of elimination.
Finally, Angle C and Angle Z. We know that these are equal do to their degree similarity of (what I think is) 65.

{B} Triangle ABC is congruent to Triangle RSQ. How do I know this?
Because Angle A is congruent to the only other angle there, Angle R.
Next, B and S are congruent. If you think of them as angles, then you can see that "angle" b is connected to the leg of AB and BC. AC has one tick mark, as does RS. BC has no tick or anything to note it's congruence. So because Point be is stick in between a leg with one tick and one leg with no tick, look for the similarity in triangle RSQ. The similarity showing as S. You should understand enough now to know how I got how C and P are congruent. 

#5) Sadly I cannot read the diagram they provide, so I cannot help with it.

#6) The length of BC: ?  The length of XZ:   ?  Measure of Angle BZX: 55 degrees. 
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Triangle ABL is an isosceles triangle in circle A with a radius of 11, PL = 16, and ∠PAL = 93°. Find the area of the circle encl
katovenus [111]

Answer:

The area of the circle enclosed by line PL and arc PL is approximately 37.62 square units

Step-by-step explanation:

The given parameters in the question are;

The radius of the circle, r = 11

The length of the chord PL = 16

The measure of angle ∠PAL = 93°

The segment of the circle for which the area is required = Minor segment PL

The shaded area of the given circle is the minor segment of the circle enclosed by line PL and arc PL

The area of a segment of a circle is given by the following formula;

Area of segment = Area of the sector - Area of the triangle

In detail, we have;

Area of segment = Area of the sector of the circle that contains the segment) - (Area of the isosceles triangle in the sector)

Area of a sector = (θ/360)×π·r²

Where;

r = The radius of the circle

θ = The angle of the sector of the circle

Plugging in the the values of <em>r</em> and <em>θ</em>, we get;

The area of the sector enclosed by arc PL and radii AP and AL = (93°/360°) × π × 11² ≈ 98.2 square units

Area of a triangle = (1/2) × Base length × Height

Therefore;

The area of ΔAPL = (1/2) × 16 × 11 × cos(93°/2) ≈ 60.58 square units

∴ The area of the segment PL ≈ (98.2 - 60.58) square units = 37.62 square units

Therefore, the area of the shaded segment PL ≈ 37.62 square units

More examples on area of a shaded segment can be found here:

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