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alexira [117]
3 years ago
11

A Basketball Tournament starts with 128 Teams.in each round half of the teams are eliminated How Many teams remain after 5 round

s
Mathematics
2 answers:
Brrunno [24]3 years ago
8 0

Total number of team in starting = 128 teams.

In each round half of the teams are eliminated.

Therefore, number of teams remain after first round = 128/2 = 64.

The number of teams remain after second round = 64/2 = 32.

The number of teams remain after third round = 32/2 = 16.

The number of teams remain after fourth round = 16/2 = 8.

The number of teams remain after fifth round = 8/2 = 4.

<h3>Therefore, after 5 rounds there remain only 4 teams.</h3>
Mazyrski [523]3 years ago
6 0

Answer: After five rounds, only 4 teams remain.

Step-by-step explanation:

at the begginning we have 128 teams, after the first round, we have half of that, this is 128/2.

after the second round, we have half of that: (128/2)/2 = 128/(2*2)

and so on, so if n is the number of rounds, the amount of theams left can be written as:

t(n) = 128/(2^n)

and for n= 5, we have:

t(5) = 128/(2^5) = 128/32 = 4

After five rounds, only 4 teams remain.

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Alla [95]

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What is the solution to the above system of equations?
kow [346]

(x , y) = (7, - 1)

2x + 3y = 11 → (1)

3x + 3y = 18 → (2)

subtracting (1) from (2) term by term eliminates the y- term

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8 0
3 years ago
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I NEED HELP PLEASE NOW
Tomtit [17]

Answer:

108

Step-by-step explanation:

4 0
3 years ago
Please answer nehjdhdhe
joja [24]
Hello!!

We know y = 7 + x. Substitute this into our other equation,

2x = (x + 7) - 10
2x = x - 3
x = -3

Now, we know that x = -3 so, we can conclude that the answer is choice B.

Hope this helps!! Let me know if you have ANY questions.
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