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harkovskaia [24]
3 years ago
13

Find a polynomial with integer coefficients that satisfies the given conditions. R has degree 4 and zeros 3 − 3i and 2, with 2 a

zero of multiplicity 2
Mathematics
1 answer:
dolphi86 [110]3 years ago
3 0

Answer:

The required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

Step-by-step explanation:

If a polynomial has degree n and c_1,c_2,...,c_n are zeroes of the polynomial, then the polynomial is defined as

P(x)=a(x-c_1)(x-c_2)...(x-x_n)

It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.

According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.

Since 3-3i is zero, therefore 3+3i is also a zero.

Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is

R(x)=(x-3+3i)(x-3-3i)(x-2)(x-2)

R(x)=((x-3)+3i)((x-3)-3i)(x-2)^2

R(x)=(x-3)^2-(3i)^2((x-3)-3i)(x-2)^2     [a^2-b^2=(a-b)(a+b)]

R(x)=(x^2-6x+9-9(i)^2((x-3)-3i)(x-2)^2

R(x)=(x^2-6x+18)(x^2-4x+4)                [i^2=-1]

R(x)=(x^2-6x+18)(x^2-4x+4)

R(x)=x^4-10x^3+46x^2-96x+72

Therefore the required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

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ipn [44]
They are easy to compare if they all have the same common denominator, then you can easily order them by the magnitude of the numerators...

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5 0
3 years ago
Find the greatest number that will divide 63, 45 and 69 so as to leave the same remainder.
jeka57 [31]

Answer:

6

Step-by-step explanation:

Let n be unknown divisor and a be the same remainder, then

63=q_1\cdot n+a\\ \\45=q_2\cdot n+a\\ \\69=q_3\cdot n+a

Subtract a from all equalities:

63-a=q_1\cdot n\\ \\45-a=q_2\cdot n\\ \\69-a=q_3\cdot n

Subtract them:

63-45=(q_1-q_2)n\Rightarrow 18=(q_1-q_2)n\\ \\69-63=(q_3-q_1)n\Rightarrow 6=(q_3-q_1)n\\ \\69-45=(q_3-q_2)n\Rightarrow 24=(q_3-q_2)n

The greatest number is 6. When you divide numbers 63, 45, 69 by 6, you'll get remainders 3, 3, 3, respectively.

7 0
3 years ago
A hiker begins a trip by first walking 22.2 km
Dominik [7]

9514 1404 393

Answer:

  20.6 km

Step-by-step explanation:

Using (East, North) coordinates, the hiker's position ends up being ...

  22.2(cos(-45°), sin(-45°)) +40.1(cos(65°), sin(65°))

We're only interested in the second coordinate of this total, which is ...

  22.2sin(-45°) +40.1sin(65°) ≈ -15.698 +36.343 = 20.645 . . . km

The y-component of the hiker's position at the end of the second day is 20.6 km north of her starting location.

4 0
3 years ago
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