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harkovskaia [24]
3 years ago
13

Find a polynomial with integer coefficients that satisfies the given conditions. R has degree 4 and zeros 3 − 3i and 2, with 2 a

zero of multiplicity 2
Mathematics
1 answer:
dolphi86 [110]3 years ago
3 0

Answer:

The required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

Step-by-step explanation:

If a polynomial has degree n and c_1,c_2,...,c_n are zeroes of the polynomial, then the polynomial is defined as

P(x)=a(x-c_1)(x-c_2)...(x-x_n)

It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.

According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.

Since 3-3i is zero, therefore 3+3i is also a zero.

Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is

R(x)=(x-3+3i)(x-3-3i)(x-2)(x-2)

R(x)=((x-3)+3i)((x-3)-3i)(x-2)^2

R(x)=(x-3)^2-(3i)^2((x-3)-3i)(x-2)^2     [a^2-b^2=(a-b)(a+b)]

R(x)=(x^2-6x+9-9(i)^2((x-3)-3i)(x-2)^2

R(x)=(x^2-6x+18)(x^2-4x+4)                [i^2=-1]

R(x)=(x^2-6x+18)(x^2-4x+4)

R(x)=x^4-10x^3+46x^2-96x+72

Therefore the required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

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Find the value of x. help with geometry pls
Ivan

Answer:

Find the value of x:-

To find Y, use Pythagorean theorem:- c^{2} =a^{2} +b^{2}

(2.1)^{2} =y^{2} +(1.4)^{2}

2.1^{2}=4.41

1.4^{2} =1.96

4.41=y^{2} +1.96

subtract 1.96 from both sides

2.45=y^{2}

y=1.5652

Now, to find x:-

x=y+y

= 1.5632+1.5652

x=3.1 \: ft

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6 0
3 years ago
Whats -5n+12n+9+(-3) some one help me with this one
nikdorinn [45]

-5n+12n+9+(-3)

-5n+12n+9-3

7n+9-3

=7n+6

Hope this helps!

Thank you for posting your question at here on Brainly.

-Charlie

8 0
3 years ago
The sum of two numbers is 43, and their product is 450. What is their difference?​
kow [346]

Answer:

List the factors of 450

1,450

3,150

5,90

6,75

9,50

10,45

15,30

18,25

The factor with the sum of 43 is 18+25

25-18=7 so the difference is 7

hope this helps

Step-by-step explanation:

8 0
3 years ago
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Write an inequality for the following graph
Tom [10]

Answer:

I am pretty sure it would be B.

7 0
2 years ago
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Suppose that the position of one particle at time is given by x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π and the position of a second p
Mashcka [7]

Answer:

there is no collision between the particles

Step-by-step explanation:

for the first particle

x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π

for the second particle

x2 = -3 + cos t, y2 = 1 + sin t, 0 ≤ t ≤ 2π

then for the collision

x1=x2 → 3*sin t = -3 + cos t → sin t= -1 + (cos t)/3→ 1+ sin t = (1/3)cos t  

y1=y2 → 1 + sin t = 2 cos t → (1/3)cos t  = 2 cos t →(1/3) = 2

since 1/3 ≠ 2 there is no collision between the particles

6 0
3 years ago
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