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musickatia [10]
2 years ago
7

A help desk with 8 employees takes up to 200 calls per hour. If every employee works 8 hours per day, how many phone calls can e

ach person take in his or her work day?
Mathematics
1 answer:
77julia77 [94]2 years ago
6 0
1 hour   -   200 calls    |multiply  8
8 hours  -  1600 calls

There are 8 employees  so every employee take  1600 : 8 = 200 phone calls daily
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3 years ago
if a toy rocket is launced vertically upward from ground level with an inital velocity of 128 feet per second, then its high h,
makkiz [27]
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-9t^2 = -81
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t^2 = 9
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3 years ago
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5 0
2 years ago
Find the radius of convergence, r, of the series. ? n2xn 7 · 14 · 21 · ? · (7n) n = 1
defon
I'm guessing the series is supposed to be

\displaystyle\sum_{n=1}^\infty\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}

By the ratio test, the series converges if the following limit is less than 1.

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7\cdot14\cdot21\cdot\cdots\cdot(7n)\cdot(7(n+1))}}{\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}}\right|

The first n terms in the numerator's denominator cancel with the denominator's denominator:

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7(n+1)}}{n^2x^n}\right|

|x^n| also cancels out and the remaining factor of |x| can be pulled out of the limit (as it doesn't depend on n).

\displaystyle|x|\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2}{7(n+1)}}{n^2}\right|=|x|\lim_{n\to\infty}\frac{|n+1|}{7n^2}=0

which means the series converges everywhere (independently of x), and so the radius of convergence is infinite.
3 0
3 years ago
Simplify <br> ‐19 ‐ 7( ‐17z + 13)<br> 4n ‐ 3( ‐9n + 13)
nataly862011 [7]

Answer:

for the first one it's 119z−110

the second one is 31n−39

i'm not sure if you wanted both together

so here just incase

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Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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