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Marianna [84]
3 years ago
7

If y varies directly as x^2, and y=2 when x=1, find y when x=10

Mathematics
2 answers:
Nikitich [7]3 years ago
6 0

Answer:

200

Step-by-step explanation:

Please refer to the attachment(s) for explanations

MissTica3 years ago
4 0

Answer:

The value of y when x = 10 is <u>200</u>

Step-by-step explanation:

Here, we have y ∝ x^2 directly

⇒ y = k × x^2

where k is the constant of proportionality.

Now, let's find k from the first information set;

we can rewrite the equation as ;

k = y/x^2

k = 2/1^2 = 2/1 = 2

The value of y when x = 10 is as follows;

y = 2 × 10^2 = 2 × 100 = 200

You might be interested in
the rectangle shown has a perimeter of 70cm and the given area. It’s length is 8 more than twice it’s width. Write and solve a s
vfiekz [6]

Dimensions of rectangle are:

Length = 26 cm

Width = 9 cm

Step-by-step explanation:

Perimeter of rectangle = 70 cm

Width= x

Length = 2x+8

We need to find the value of length and width of rectangle.

The formula used is:

Periemter\,\,of\,\,rectangle=2(Length+Width)

Putting values:

Periemter\,\,of\,\,rectangle=2(Length+Width)\\70=2(2x+8+x)\\70=2(3x+8)\\70=6x+16\\70-16=6x\\54=6x\\x=54/6\\x=9

So, Value of Width = x = 9 cm

Value of Length = 2x+8 = 2(9)+8 = 18+8=26 cm

So Dimensions of rectangle are:

Length = 26 cm

Width = 9 cm

Keywords: Perimeter of rectangle

Learn more about Perimeter of rectangle at:

  • brainly.com/question/6594923
  • brainly.com/question/1822996
  • brainly.com/question/2860697

#learnwithBrainly

6 0
3 years ago
Wats da anwser 4×70=4×7×_
Veseljchak [2.6K]
10 will be your answer
6 0
3 years ago
Read 2 more answers
Please help fast!!!!!!!
garri49 [273]

Answer:

l am sorry l do not get the question

8 0
3 years ago
HELP PLEASE!!!!!!!!!!!!
Bogdan [553]

Answer:

See the explanation.

Step-by-step explanation:

We are given the function f(x) = x² + 2x - 5

Zeros :

If f(x) = 0 i.e. x² + 2x - 5 = 0

The left hand side can not be factorized. Hence, use Sridhar Acharya formula and  

x= \frac{-2+\sqrt{2^{2}-4\times(-5)\times1 } }{2} and  

x= \frac{-2-\sqrt{2^{2}-4\times(-5)\times1 } }{2}

⇒ x = -3.45 and 1.45

Y- intercept :

Putting x = 0, we get, f(x) = - 5, Hence, y-intercept is -5.

Maximum point :

Not defined

Minimum point:  

The equation can be expressed as (x + 1)² = (y + 5)

This is an equation of parabola having the vertex at (-1,-5) and axis parallel to + y-axis

Therefore, the minimum point is (-1,-5)

Domain :  

x can be any real number

Range:  

f(x) ≥ - 6

Interval of increase:

Since this is a parabola having the vertex at (-1,-5) and axis parallel to + y-axis.

Therefore, interval of increase is +∞ > x > -1

Interval of decrease:

-∞ < x < -1

End behavior :  

f(x) = x^{2} +2x-5 =x^{2}  (1+\frac{2}{x} -\frac{5}{x^{2} } )

So, as x tends to +∞ , then f(x) tends to +∞

And as x tends to -∞, then f(x) tends to +∞. (Answer)

7 0
3 years ago
Solve for x, 12y+6=6(y+1)
Vanyuwa [196]

For this case we must solve the following equation:

12y + 6 = 6 (y + 1)

We apply distributive property on the right side of the equation:

12y + 6 = 6y + 6

We subtract 6y on both sides of the equation:

12y-6y + 6 = 6\\6y + 6 = 6

We subtract 6 from both sides of the equation:

6y = 6-6\\6y = 0

Dividing by 6 on both sides of the equation:

y = 0

So, the result is y = 0

Answer:

y = 0

4 0
3 years ago
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