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Marianna [84]
3 years ago
7

If y varies directly as x^2, and y=2 when x=1, find y when x=10

Mathematics
2 answers:
Nikitich [7]3 years ago
6 0

Answer:

200

Step-by-step explanation:

Please refer to the attachment(s) for explanations

MissTica3 years ago
4 0

Answer:

The value of y when x = 10 is <u>200</u>

Step-by-step explanation:

Here, we have y ∝ x^2 directly

⇒ y = k × x^2

where k is the constant of proportionality.

Now, let's find k from the first information set;

we can rewrite the equation as ;

k = y/x^2

k = 2/1^2 = 2/1 = 2

The value of y when x = 10 is as follows;

y = 2 × 10^2 = 2 × 100 = 200

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Write the expression as a single natural logarithm;<br> 3 ln 3 + 2 ln x
crimeas [40]

Answer:

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Step-by-step explanation:

Given in the question an expression

3 ln 3 + 2 ln x

Step1

Apply power rule

mlnx=lnx^{m}

ln 3³ +  ln x²

Step2

Apply multiplication rule

lnx + lny=ln(xy)

ln (3³ . x²)

3³ = 27

so

ln (27x²)

4 0
3 years ago
Read 2 more answers
How do i figure out these problems ?
Andreyy89

Given two vectors

v=(a,b),\quad w=(c,d)

they are parallel if they are a multiple of each other:

c=ka,\quad d=kb

You can easily test this by checking if

\dfrac{c}{a}=\dfrac{d}{b}

they are orthogonal if their dot product is null:

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For example, in the first case, we have

\dfrac{10}{3}\div 2 \neq \dfrac{4}{3}\div 5

So, they aren't parallel. Similarly, you have

2\cdot \dfrac{10}{3}+5\cdot \dfrac{4}{3}\neq 0

So, they aren't orthogonal.

In the second case, we have

\dfrac{5}{-12}\neq \dfrac{-6}{-10}

So, they aren't parallel, and

5(-12)+(-6)(-10)=-60+60=0

So, they are orthogonal.

Finally, we have

\dfrac{2}{-4}=\dfrac{-7}{14}=-\dfrac{1}{2}

So, they are parallel (and thus can't be orthogonal)

7 0
3 years ago
Which equation shows that the Pythagorean identity is true for theta = 2pi? Select
Andreyy89

Answer:

I just took the quiz

Step-by-step explanation:

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Also known as C.

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Irina-Kira [14]

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Step-by-step explanation:

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