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Marianna [84]
3 years ago
7

If y varies directly as x^2, and y=2 when x=1, find y when x=10

Mathematics
2 answers:
Nikitich [7]3 years ago
6 0

Answer:

200

Step-by-step explanation:

Please refer to the attachment(s) for explanations

MissTica3 years ago
4 0

Answer:

The value of y when x = 10 is <u>200</u>

Step-by-step explanation:

Here, we have y ∝ x^2 directly

⇒ y = k × x^2

where k is the constant of proportionality.

Now, let's find k from the first information set;

we can rewrite the equation as ;

k = y/x^2

k = 2/1^2 = 2/1 = 2

The value of y when x = 10 is as follows;

y = 2 × 10^2 = 2 × 100 = 200

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