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nlexa [21]
3 years ago
8

There are 8 times as many males as females on the maths course at university. What fraction of the course are female? Give your

answer in its simplest form.
Mathematics
1 answer:
Advocard [28]3 years ago
3 0

Answer:

⅑

Step-by-step explanation:

Let m represents number of males, and f represents number of females taking the maths course.

Given that number of males (m) taking the maths course is 8 times as much as number of females (f), total number of students taking the maths course (T).

Thus we can represent the information above with the following:

m = no. of males

f = no. of females

T = Total

m = 8f

T = m + f

Thus,

Total = 8f + f = 9f

==>The fraction of the course that are females = No. of females (f) ÷ Total no. of students (T)

= f/9f

Fraction of females in simplified form would be ⅑

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Hello macelynn190!

\huge \boxed{\mathfrak{Question} \downarrow}

\huge \tt \frac{5 - 2(a + 3b)}{2}

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

To solve this question we need to substitute the given values of 'a' & 'b' in the equation & then simplify it.

Given,

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Now, substitute this in the place of 'a' & 'b'..

\large \tt \frac{5 - 2(a + 3b)}{2}  \\  =  \large   \underline{\underline{\tt \:  \frac{5 - 2((4) + 3(1))}{2} }}

Lastly, simplify it...

\large   \tt \:  \frac{5 - 2((4) + 3(1))}{2}  \\  =   \large \tt\frac{5 - 2(4 + 3)}{2}  \\  =  \large \tt \:  \frac{5 - 2(7)}{2}  \\  =  \large \tt \: \frac{5 - 14}{2}  \\  =  \large \tt\frac{-9}{2}  \\  = \large  \boxed{\boxed{  \bf \: -\frac{9}{2}=-4.5}}

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