13 is the answer for ur question
Yes it can, but jost once
Answer:
1) 10.55%
2) 30.77%
Step-by-step explanation:
52/52•39/51•26/50•13/49 = 0.105498... ≈ 10.55%
100% chance you draw a unique card on the first draw
51 cards left of which 13(3) = 39 are unique suit for your second draw
50 cards left of which 13(2) = 26 are unique suit for your third draw
49 cards left of which 13(1) = 13 are unique suit for your forth draw.
Two balls are already green
Leaves 4 red balls in a field of 13 balls
4/13 = 0.307692... ≈ 30.77%
Based on the given inequality of y≥ x - 1, the graph that matches it best is C. Graph A.
<h3>How are inequalities graphed?</h3>
When graphing an inequality with the "greater or equal" and "less or equal" signs, the line will be a steady line as shown by graphs A and B.
If y is the larger or equal variable, the shaded area will be to the left of the line.
The inequality is y≥ x - 1 which means that the line should be steady and the shading should be on the left of the line. Graph A is therefore the correct graph.
Find out more on graphing inequalities at brainly.com/question/11234618.
#SPJ1
Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]
Answer:
Yes they are
Step-by-step explanation:
In the triangle JKL, the sides can be calculated as following:
=> JK = 
=> JL = 
=> KL = 
In the triangle QNP, the sides can be calculate as following:
=> QN = ![\sqrt{[-3-(-4)]^{2} + (0-4)^{2} } = \sqrt{1^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B-3-%28-4%29%5D%5E%7B2%7D%20%2B%20%280-4%29%5E%7B2%7D%20%20%7D%20%3D%20%5Csqrt%7B1%5E%7B2%7D%2B%28-4%29%5E%7B2%7D%20%20%7D%20%3D%20%5Csqrt%7B1%2B16%7D%3D%5Csqrt%7B17%7D)
=> QP = ![\sqrt{[-7-(-4)]^{2} + (1-4)^{2} } = \sqrt{(-3)^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B-7-%28-4%29%5D%5E%7B2%7D%20%2B%20%281-4%29%5E%7B2%7D%20%20%7D%20%3D%20%5Csqrt%7B%28-3%29%5E%7B2%7D%2B%28-3%29%5E%7B2%7D%20%20%7D%20%3D%20%5Csqrt%7B9%2B9%7D%3D%5Csqrt%7B18%7D%20%3D%203%5Csqrt%7B2%7D)
=> NP = ![\sqrt{[-7-(-3)]^{2} + (1-0)^{2} } = \sqrt{(-4)^{2}+1^{2} } = \sqrt{16+1}=\sqrt{17}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B-7-%28-3%29%5D%5E%7B2%7D%20%2B%20%281-0%29%5E%7B2%7D%20%20%7D%20%3D%20%5Csqrt%7B%28-4%29%5E%7B2%7D%2B1%5E%7B2%7D%20%20%7D%20%3D%20%5Csqrt%7B16%2B1%7D%3D%5Csqrt%7B17%7D)
It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP
=> They are congruent triangles