Question

Find the 8th term of the geometric sequence whose common ratio is 1/3 and whose first term is 7

Answer 1

Answer:

$\frac{7}{2187}$

Step-by-step explanation:

The n th term of a geometric sequence is

$a_{n}$ = a$(r)^{n-1}$

where a is the first term and r the common ratio, thus

$a_{8}$ = 7$(1/3)^{7}$ = 7 × $\frac{1}{2187}$ = $\frac{7}{2187}$