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2 years ago

Find the solution please

Mathematics

1 answer:

Misha Larkins [42]2 years ago

4 0

I got the answer (-1, 1) hope this helps

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Lin's teacher uses the box to store her set of cubes with an edge length of one half inch. if the box is completely full, how ma

nlexa [21]

Answer:

448 cubes

Step-by-step explanation:

Volume of cubes fitted in the box will be equal to the cumulative volume of the cubes.

Since, volume of a cube = (Side)³

Side of the cube = $\frac{1}{2}$ inch

Therefore, volume of the cube = $(\frac{1}{2})^3=\frac{1}{8}$ inches

Volume of the storage box = 56 cubic inches

Since, number of cubes fitted in the storage box = $\frac{\text{Volume of the storage box}}{\text{Volume of one cube}}$

= $\frac{56}{\frac{1}{8}}$

= 56 × 8

= 448 cubes

Therefore, number of cubes fitted in the storage box = 448

3 0

2 years ago

If two angles are supplementary, their sum equals

Black_prince [1.1K]

If two angles are supplementary, their sum equals 180 degrees

7 0

3 years ago

A person in a balloon which is 2,000 feet above the airport finds that the angle of depression to a ship out at sea is 21°. Find

maria [59]

The horizontal distance is given by the formula:
tan θ=opposite/adjacent
where:
θ=21
opposite=2000 ft
adjacent=a
thus calculating for a we get:
tan 21=2000/a
thus
a=2000/tan 21
a=5210.18 ft

Answer: 5210.18 ft

4 0

3 years ago

Read 2 more answers

16) Please help with question. WILL MARK BRAINLIEST + 10 POINTS.

Katyanochek1 [597]

We will use the sine and cosine of the sum of two angles, the sine and consine of $\frac{\pi}{2}$ , and the relation of the tangent with the sine and cosine:

$\sin (\alpha+\beta)=\sin \alpha\cdot\cos\beta + \cos\alpha\cdot\sin\beta

\cos(\alpha+\beta)=\cos\alpha\cdot\cos\beta-\sin\alpha\cdot\sin\beta$

$\sin\dfrac{\pi}{2}=1,\ \cos\dfrac{\pi}{2}=0$

$\tan\alpha = \dfrac{\sin\alpha}{\cos\alpha}$

If you use those identities, for $\alpha=x,\ \beta=\dfrac{\pi}{2}$ , you get:

$\sin\left(x+\dfrac{\pi}{2}\right) = \sin x\cdot\cos\dfrac{\pi}{2} + \cos x\cdot\sin\dfrac{\pi}{2} = \sin x\cdot0 + \cos x \cdot 1 = \cos x$

$\cos\left(x+\dfrac{\pi}{2}\right) = \cos x \cdot \cos\dfrac{\pi}{2} - \sin x\cdot\sin\dfrac{\pi}{2} = \cos x \cdot 0 - \sin x \cdot 1 = -\sin x$

Hence:

$\tan \left(x+\dfrac{\pi}{2}\right) = \dfrac{\sin\left(x+\dfrac{\pi}{2}\right)}{\cos\left(x+\dfrac{\pi}{2}\right)} = \dfrac{\cos x}{-\sin x} = -\cot x$

3 0

3 years ago

Check

algol [13]

Answer: Option A is the correct answer, y = x + 2

y - 3 = x-1

Step-by-step explanation:

6 0

2 years ago