Answer:
PQ = 
Step-by-step explanation:
given MQR = 60, PQR = 75
MQP = 75 -60= 15
WE KNOW THAT MQR +QRM +QMR = 180
MPQ = MQP AS ANGLE OPPOSITE TO EQUAL SIDES ARE EQUAL
THEREFORE QMR = 90 - 60 = 30
therefore PQM = 75 - 60 = 15
PM = PQ because M is the mid point
therefore PR = PM + 
PR = 
PQ =
Given that mean=3750 hours and standard deviation is 300:
Then:
<span>a. The probability that a lamp will last for more than 4,000 hours?
P(x>4000)=1-P(x<4000)
but
P(x<4000)=P(z<Z)
where:
z=(x-</span>μ)/σ
z=(4000-3750)/300
z=0.833333
thus
P(x<4000)=P(z<0.8333)=0.7967
thus
P(x>4000)=1-0.7967=0.2033
<span>b.What is the probability that a lamp will last less than 3,000 hours?
P(x<3000)=P(z<Z)
Z=(3000-3750)/300
z=-2.5
thus
P(x<3000)=P(z<-2.5)=0.0062
c. </span><span>.What lifetime should the manufacturer advertise for these lamps in order that only 4% of the lamps will burn out before the advertised lifetime?
the life time will be found as follows:
let the value be x
the value of z corresponding to 0.04 is z=-2.65
thus
using the formula for z-score:
-2.65=(x-3750)/300
solving for x we get:
-750=x-3750
x=-750+3750
x=3000</span>
1=81 centimetres
1=82 centimetres
2=83 centimetres
3=84 centimetres
1=85 centimetres
Answer:
A
Step-by-step explanation:
This is a Bernoulli trial problem.
Since the probability that the seed will germinate is 80% or 0.8, the probability that they won’t germinate is 0.2
Now let’s say the probability to germinate is p and the probability not to is a, we can now set up the Bernoulli equation in this regard. Since we are proposing that exactly 14 will germinate, it means 6 are not expected to germinate
P(14) = 20C14 (0.8)^14 (0.2)^6 = 0.109099700973
Option A is the right answer
Answer:
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Step-by-step explanation:
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