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Sloan [31]
3 years ago
5

Which is the answer and how did you solve it?

Mathematics
1 answer:
motikmotik3 years ago
3 0
Its pretty simple

9x-7y = 22
x + 3y = -24

(9x-7y = 22)
-9(x + 3y = -24)
= -9x -27y = 216
+ 9x-7y = 22
= -34y = 238
= / -34 = 238/-34
y = -7

now plug -7 in one of the equation
x + 3(-7) = -24
x -21 = -24
+21. +21
x = -3

so answer is x = -3 and y = -7

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1 1/5 divided by 3 4/5
Nana76 [90]

Answer:

6 /19

≅ 0.3157895

Step-by-step explanation:

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2 years ago
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How to graph this? Please asap
iVinArrow [24]
I hope this helps you

4 0
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Six students collect buttons for a project. The students have 10, 14, 15, 12, 13, and 14 buttons. They divide the buttons evenly
vovangra [49]

Answer:

13 buttons

Step-by-step explanation:

The first step is to add the buttons received by the 6 students.

= 10 + 14 + 15 + 12 + 13 + 14

= 78 buttons

Therefore the number of buttons received by each students can be calculated as follows

= 78/6

= 13 buttons

Hence each student will receive 13 buttons

6 0
2 years ago
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Soap films and bubbles are colorful because the interference conditions depend on the angle of illumination (which we aren't cov
mylen [45]

Answer:

56.39 nm

Step-by-step explanation:

In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,

2t=(m+\frac{1}{2} ).\frac{\lambda}{n}

where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...

Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.

In order to have its longest constructive reflection at the red end (700 nm)

t_1=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_1=\frac{1}{2} .\frac{700}{(2)*(1.33)}\\ \\ t_1=131.58\ nm

Here we take m=0.

Similarly for the constructive reflection at the blue end (400 nm)

t_2=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_2=\frac{1}{2} .\frac{400}{(2)*(1.33)}\\ \\ t_2=75.19\ nm

Hence the thickness difference should be

t_1-t_2=131.58-75.19=56.39 \ nm

7 0
2 years ago
Solve for z. 5z – 8 = 32
jarptica [38.1K]
The answer would be 8
5 0
3 years ago
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