In this exercise we have to use the knowledge of geometric progression to find three specific numbers, in this way we can say that these numbers correspond to;
Then using the formula of the geometric progression we find that:
now, the differences between the terms must be the same:
and now, when we increase the third term by 9,so we have:
Now we use that identity in the first equation :
The general solution for a quadratic equation is
We have that:
so, put the numbers in the formula we find:
See more about geometric progress at brainly.com/question/14320920
Answer:
you have to do the directions they gave you, draw the coordinates
Step-by-step explanation:
Answer:
Step-by-step explanation:
153•0.92^x is a decaying exponential function.
In theory these functions never reach zero.
Suppose that you were willing to change the problem to read:
"What value will x have to for the first number to come within 0.0001 of zero?" Solve 153•0.92^x = 0.0001.
To do this, take the common log of both sides, obtaining
log 153 + x*log 0.92 = log 0.0001
Note that log 0.0001 = -4; log 153 = 2.18469; and log 0.92 = -0.03621.
Then we have:
2.18469 + x(-0.03621) = - 4.
Isolate the 2nd term. To accomplish this, subtract 2.18469 from both sides, obtaining:
-0.03621x = -6.18469
Isolate x by dividing both sides by -0.03621:
x = 170.8
This tells us that as x approaches +179, the quantity 153·0.92x will be within 0.0001 of zero.
Answer:
2 i think tbh ide.k
Step-by-step explanation: