A right triangle has a hypotenuse length of 13 units. One leg has a length of 12 units. Which equation can be used to determine the length of the other leg? Group of answer choices
LaTeX: a^2=12^2+13^2 a 2 = 12 2 + 13 2
LaTeX: a=\sqrt{13^2-12^2} a = 13 2 − 12 2
LaTeX: a^2=12^2-13^2 a 2 = 12 2 − 13 2
LaTeX: a=\sqrt{12^2+13^2} a = 12 2 + 13 2
2 answers:
Answer:
The length of the other leg is 12
We know that a²+b²=c²
So if you follow the pythagorean theorem, we substitute the hypotenuse for c² and the leg (12) for either a² or b² because a and b are both legs, so it doesn't matter.
now we have a²+12²=13²
But I usually take the shortcut..and instead of a²+12²=13²
I subtract 12² from 13² (it's the same thing)
After you subtract 13²-12²=a²...you find the square root of 13²-12²
so the answer is LaTeX: a=\sqrt{13^2-12^2}
a= square root of 13²-12²
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Step-by-step explanation:
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Answer:
Step-by-step explanation:
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