If you go on my profile you will see a similar problem that I already answered today.
Lets start by using a formula (don't remember the name)
(y-y1)=M(x-x1)
M is slope and y is first y value and y1 is second y value same applies to X.
Substitute in the values.
(5-q) = 10(-6-(-7))
5-q = 10*(1)
5-q = 10
-q = 5
q = -5
Check:
Substitute in the value of "q" and use the formula to find slope:
(y1-y)/(x1-x)
Substitute
(-5-5)/(-7-(-6))
-10/-1
10
Your Answer:
The value of "q" is -5
(8x^2-9y^2-4x)+(x^2-3y^2-7x)
First, get rid of the parentheses and combine like terms
(8x^2+x^2)(-9y^2-3y^2)(-4x-7x)
9x^2-12y^2-11x is your answer
Answer:
the answer is 6x+11
Step-by-step explanation:
1/4(12+16)+3x+7
1/4×4(3x+4)+3x+7
(3x+4)+3x+7
3x+4+3x+7
6x+11
Answer:
slope = 2
Step-by-step explanation:
To find the slope, we need to read 2 points off the graph.
Where the line crosses the y-axis, the point is (0, 2.5).
The next point up on the line looks like (1, 4.5).
slope = m = (difference in y)/(difference in x)
To find the difference in y and difference in x, subtract the y-coordinates and the x-coordinates, respectively, in the same order.
difference in y = 4.5 - 2.5 = 2
difference in x = 1 - 0
slope = m = (difference in y)/(difference in x) = 2/1 = 2
