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3 years ago

Let theta be an angle in quadrant III such that cos theta=-3/5 .

1 answer:

5 0

Using
$\sin^2 x + \cos^2 x = 1$
$\sin^2 \theta + (-3/5)^2 = 1$
$\sin^2 \theta + 9/25 = 1$
$\sin^2 \theta = 1-9/25 = (25-9)/25 = 16/25$
$\sin \theta = \pm 4/5$
in 3rd quadrant, sin is negative.
so
$\sin \theta = -4/5$

now,
csc theta = 1/ sin theta = -5/4

tan theta = sin theta/ cos theta = -4/5 / -3/5 = + 4/3

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At the grocery store Ayla buys1 1/3 pounds of ground turkey .Tasha buys 2 times as much ground turkey . How much ground turkey d

viktelen [127]

Answer:

2 2/3 lbs

Step-by-step explanation:

Convert Alya's mixed number to an improper fraction

3*1+1 = 4/3

multiply 4/3 times 2/1

4*2 = 8

3*1 = 3

8/3 - convert back to mixed number

8/3 = 2 2/3

4 0

3 years ago

My pigg y bank has only pennies and nicklels in it , and 2/7 of the coins are nickel If i remove 84 pennies then 1/3 of the reme

zubka84 [21]

Answer:

There are 105 pennies in the piggy bank.

There are 42 nickels in the piggy bank.

Step-by-step explanation:

there are:

p pennies in the piggy bank

n nickels in the piggy bank

Then we can define T, the total number of coins, as:

T = p + n

We know that 2/7 of the total number of coins are nickels.

This can be written as:

n = (2/7)*T = (2/7)*(n + p)

And if we remove 84 pennies, 1/3 of the remaining coins are pennies.

This can be written as:

p - 84 = (1/3)*(n + p - 84)

Then we have a system of two equations:

n = (2/7)*(n + p)

p - 84 = (1/3)*(n + p - 84)

Let's solve the system, to do it, we first need to isolate one of the variables in one of the equations.

We can isolate n in the first one, to get:

n = (2/7)*(n + p) = (2/7)*n + (2/7)*p

n - (2/7)*n = (2/7)*p

n*(5/7) = (2/7)*p

n = (7/5)*(2/7)*p = (2/5)*p

n = (2/5)*p

Now we can replace this in the other equation:

p - 84 = (1/3)*(n + p - 84)

p - 84 = (1/3)*( (2/5)*p + p - 84)

Let's solve this for p

p - 84 = (1/3)*( (7/5)*p - 84)

3*(p - 84) = (7/5)*p - 84

3p - 252 = (7/5)*p - 84

3*p - (7/5)*p = 252 - 84

(15/5)*p - (7/5)*p = 168

(8/5)*p = 168

p = (5/8)*168 = 105

There are 105 pennies in the piggy bank.

And we know that:

n = (2/5)*p = (2/5)*105 = 42

There are 42 nickels in the piggy bank.

4 0

3 years ago

Help me with my algebra final exam please.

kvasek [131]

Answer:

its b

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Product in standard form (explain) (3+6i)(4+9i)

ololo11 [35]

First you have to factor (aka, multiply) your binomial (which is what you have written) usually it helps to organize your thinking, and help tell what you need to multiply, to use the binomial chicken(or crab claw, what ever you want to call it) which basically you draw two arches, one arch connecting the 3 and 4, and then the other the 3 and 9i. on the opposite side (depending on wheater you connected then from the top or bottom) you connect (with an arch) the 6i and the four, and then the 6i to the 9i.

so now you multiply each piece you've connected:
3 x 4= 12
3 x 9i= 27i
6i x 4= 24i
6i x 9i= 54i^2

after you've done this you can move on to putting it into standard form, which just means you put things in descending order, depending on how many exponents the x (or in this case i) has.
your largest exponent is 54i^2, so that's first in out equation, next 27i, and 24i (you can combine these because they are like term) which equals 51i, after that you just add the 12 on the end, so the final equation looks like this:

54i^2+51i+12

4 0

3 years ago

Evaluate the integral by making an appropriate change of variables.

VARVARA [1.3K]

By inspecting the integrand, the "obvious" choice for substitution would be

u = y + x

v = y - x

Solving for x and y, we would have

x = (u - v)/2

y = (u + v)/2

in which case the Jacobian and its determinant are

$J=\begin{bmatrix}x_u&x_v\\y_u&y_v\end{bmatrix}=\dfrac12\begin{bmatrix}1&-1\\1&1\end{bmatrix}\implies|\det J|=\left|\dfrac12\right|=\dfrac12$