Answer:
The time elapsed is 0.017224 s
Solution:
As per the question:
Analog signal to digital bit stream conversion by Host A =64 kbps
Byte packets obtained by Host A = 56 bytes
Rate of transmission = 2 Mbps
Propagation delay = 10 ms = 0.01 s
Now,
Considering the packets' first bit, as its transmission is only after the generation of all the bits in the packet.
Time taken to generate and convert all the bits into digital signal is given by;
t = 
t = 
(Since, 1 byte = 8 bits)
t = 7 ms = 0.007 s
Time Required for transmission of the packet, t':
Now, the time elapse between the bit creation and its decoding is given by:
t + t' + propagation delay= 0.007 + 
+ 0.01= 0.017224 s
The SOA is the specific record type found in every zone and contains information that identifies the sever primarily responsible for the zone as well as some operational properties for the zone.
Explanation:
The Start of Authority Records (SOA) has the following information they are
Serial Number: This number is used to find when zonal information should be replicated.
Responsible person: The Email address of a person is responsible for managing the zone.
Refresh Interval: It specifies how often a secondary DNS server tries to renew its zone information.
Retry Interval: It specifies the amount of time a secondary server waits before retrying the zone information has failed.
Expires After: IT specifies the amount of time before a secondary server considers its zone data if it can't contact with the primary server.
Minimum TTL: It specifies the default TTL value for a zone data when a TTL is not supplied.
Answer:
A I think I might be wrong
Answer:
Canada launched the national Generation Energy Council of leading Canadians, who proposed principles to the Government of Canada on how to build our energy future. Today, these principles guide government decisions to support Canadian families, businesses, and communities. Together, we are: saving energy powering clean communities.
Explanation:
Answer:
c) it will always return with an answer of 7 or fewer comparisons of data.
Explanation:
As maximum number of comparison in worst case for sorted binary search is log₂n, here n = 100, so maximum search is at least 6.6 which is approximately 7.
