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Colt1911 [192]
3 years ago
11

Earning wise scope of web and mobile app development

Computers and Technology
1 answer:
lubasha [3.4K]3 years ago
3 0

Answer:

Mobile are build in a specific platform such as Android, iOS ect and they use application such as apple store and have access to the system such as GPS and the camera. Mobile apps live and run on mobiles as on they are their own thing controlled by a developer on the other end

Explanation:

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Write a program which populates an array with integer values read from a file. We do not know how many integers are in the file,
max2010maxim [7]

Answer:

#include <stdio.h>

#include <stdlib.h>

#include <string.h>

int main()

{

int arr[100];

int i = 0;

int j = 0;

char c[10];

char temp;

int sum = 0;

FILE* fp;

if ((fp = fopen("test.txt", "r")) == NULL) {

printf("cannot open the file");

return;

}

else {

do {

temp = fgetc(fp);

if (temp == ' ' || temp == '\n') {

c[j] = '\0';

arr[i++] = atoi(c);

j = 0;

continue;

}

c[j++] = temp;

} while (temp != EOF);

for (j = i - 1; j >= 0; j--) {

printf("%d\n", arr[j]);

}

}

getchar();

}

Explanation:

5 0
3 years ago
The mathematical constant Pi is an irrational number with value approximately 3.1415928... The precise value of this constant ca
tatiyna

Answer:

I am writing a Python program:

def approxPIsquared(error):

   previous = 8

   new_sum =0

   num = 3

   while (True):

       new_sum = (previous + (8 / (num ** 2)))

       if (new_sum - previous <= error):

           return new_sum

       previous = new_sum

       num+=2    

print(approxPIsquared(0.0001))

Explanation:

I will explain the above function line by line.

def approxPIsquared(error):  

This is the function definition of approxPlsSquared() method that takes error as its parameter and approximates constant Pi to within error.

previous = 8     new_sum =0      num = 3

These are variables. According to this formula:

Pi^2 = 8+8/3^2+8/5^2+8/7^2+8/9^2+...

Value of previous is set to 8 as the first value in the above formula is 8. previous holds the value of the previous sum when the sum is taken term by term. Value of new_sum is initialized to 0 because this variable holds the new value of the sum term by term. num is set to 3 to set the number in the denominator. If you see the 2nd term in above formula 8/3^2, here num = 3. At every iteration this value is incremented by 2 to add 2 to the denominator number just as the above formula has 5, 7 and 9 in denominator.

while (True):  This while loop keeps repeating itself and calculates the sum of the series term by term, until the difference between the value of new_sum and the previous is less than error. (error value is specified as input).

new_sum = (previous + (8 / (num ** 2)))  This statement represents the above given formula. The result of the sum is stored in new_sum at every iteration. Here ** represents num to the power 2 or you can say square of value of num.

if (new_sum - previous <= error):  This if condition checks if the difference between the new and previous sum is less than error. If this condition evaluates to true then the value of new_sum is returned. Otherwise continue computing the, sum term by term.

return new_sum  returns the value of new_sum when above IF condition evaluates to true

previous = new_sum  This statement sets the computed value of new_sum to the previous.

For example if the value of error is 0.0001 and  previous= 8 and new_sum contains the sum of a new term i.e. the sum of 8+8/3^2 = 8.88888... Then IF condition checks if the

new_sum-previous <= error

8.888888 - 8 = 0.8888888

This statement does not evaluate to true because 0.8888888... is not less than or equal to 0.0001

So return new_sum statement will not execute.

previous = new_sum statement executes and now value of precious becomes 8.888888...

Next   num+=2  statement executes which adds 2 to the value of num. The value of num was 3 and now it becomes 3+2 = 5.

After this while loop execute again computing the sum of next term using       new_sum = (previous + (8 / (num ** 2)))  

new_sum = 8.888888.. + (8/(5**2)))

This process goes on until the difference between the new_sum and the previous is less than error.

screenshot of the program and its output is attached.

6 0
3 years ago
A(n) ____________________ stores copies of data or programs that are located on the hard drive and that might be needed soon in
Katarina [22]
Https://m.youtube.com/watch?v=d-5dc8CuOvw
6 0
3 years ago
Write an expression that executes the loop body as long as the user enters a non-negative number. Note: If the submitted code ha
madam [21]

Answer:

           while (Num>=0) {

               System.out.println("enter a another number");

               Num = in.nextInt();

           }

Explanation:

The complete java code prompting a user to enter a number until a negative number is entered is given below:

import java.util.Scanner;

public class num6 {

public static void main (String [] args) {

Scanner in = new Scanner(System.in);

System.out.println("enter a number");

int Num = in.nextInt();

while (Num>=0) {

System.out.println("enter a another number");

Num = in.nextInt();

}

System.out.println("Done.");

return;

}

}

3 0
3 years ago
Which statement best explains the way that similar apps are used in different devices?
monitta

The statement that  best explains the way that similar applications are used in different devices is option b:  Although the systems are different, the apps are still designed to work the same way.

<h3>How does an app work?</h3>

An app is known to be a kind of a software that gives room for a person to be able to carry out some specific tasks.

Note that Applications for desktop or laptop computers are said to be called desktop applications and those apps that are used in mobile devices are known to be called mobile apps.

Hence, The statement that  best explains the way that similar apps are used in different devices is option b:  Although the systems are different, the apps are still designed to work the same way.

Learn more about Software applications from

brainly.com/question/22442533

#SPJ1

6 0
2 years ago
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