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MAVERICK [17]
3 years ago
6

Can you help me please?

Mathematics
1 answer:
morpeh [17]3 years ago
7 0

\bf 3\sqrt{2}-\sqrt{50}+3-\sqrt{8}+\sqrt{288}-\sqrt{9}~~ \begin{cases} 50=2\cdot 5\cdot 5\\ \qquad 2\cdot 5^2\\ 8=2\cdot 2\cdot 2\\ \qquad 2^2\cdot 2\\ 288=2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 3\cdot 3\\ \qquad 2^4\cdot 2\cdot 3^2\\ \qquad 2 (2^2)^2 3^2\\ \qquad 2(2^2 3)^2\\ \qquad 2(12)^2\\ 9=3^2 \end{cases}


\bf 3\sqrt{2}-\sqrt{2\cdot 5^2}+3-\sqrt{2^2\cdot 2}+\sqrt{2\cdot 12^2}-\sqrt{3^2} \\\\\\ 3\sqrt{2}-5\sqrt{2}+3-2\sqrt{2}+12\sqrt{2}-3 \\\\\\ 3\sqrt{2}-5\sqrt{2}-2\sqrt{2}+12\sqrt{2}+3-3\implies \stackrel{\textit{adding like-terms}}{8\sqrt{2}}

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Use the distributive property to simplify the expressions. 1B. -3(9x-q) 2B. 2(12+5p) 3b. -7(-8y+7) 4b. 10(2+7c) 5b. -8(7+11k) 6b
Debora [2.8K]
1B: -3(9x-q)
       -27x + 3q


Step 1: Distribute the -3 to the 9x to get -27x.
Step 2: Distribute the -3 to the -q.


2B: 2(12+5p)
       24 + 10p

Step 1: Distribute the 2 to the 12 to get 24.
Step 2: Distribute the 2 to the 5p to get 10p.

3B: -7(-8y+7)
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Step 1: Distribute the -7 to the -8y to get 56y.
Step 2: Distribute the -7 to the 7 to get -49.

4B: 10(2+7c)
        20 + 70c


Step 1: Distribute the 10 to the 2 to get 20. 
Step 2: Distribute the 10 to the 7c to get 70c.

5B: -8(7+11k)
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Step 1: Distribute the -8 to the 7 to get -56.
Step 2: Distribute the -8 to the 11k to get -88k.

6B: -(3-7u)
       -1(3-7u)
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Step 1: Place a 1 after the negative symbol to symbolize -1.
Step 2: Distribute the -1 to the three to get -3.
Step 3: Distribute the -1 to the -7u to get 7u.


7B: -6(5p + s)
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Step 1: Distribute the -6 to the 5p to get -30p.
Step 2: Distribute the -6 to the s to get -6s.

:) :D




8 0
3 years ago
Factor the perfect square trinomials<br>a2+20a+100​
sukhopar [10]

Answer:

-10

Step-by-step explanation:

a^{2} +(10+10)a+100

a^{2} +10a+10a+100

a(a+10)+10(a+10)

(a+10)(a+10)

so,a=-10

6 0
3 years ago
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