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MAVERICK [17]
3 years ago
6

Can you help me please?

Mathematics
1 answer:
morpeh [17]3 years ago
7 0

\bf 3\sqrt{2}-\sqrt{50}+3-\sqrt{8}+\sqrt{288}-\sqrt{9}~~ \begin{cases} 50=2\cdot 5\cdot 5\\ \qquad 2\cdot 5^2\\ 8=2\cdot 2\cdot 2\\ \qquad 2^2\cdot 2\\ 288=2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 3\cdot 3\\ \qquad 2^4\cdot 2\cdot 3^2\\ \qquad 2 (2^2)^2 3^2\\ \qquad 2(2^2 3)^2\\ \qquad 2(12)^2\\ 9=3^2 \end{cases}


\bf 3\sqrt{2}-\sqrt{2\cdot 5^2}+3-\sqrt{2^2\cdot 2}+\sqrt{2\cdot 12^2}-\sqrt{3^2} \\\\\\ 3\sqrt{2}-5\sqrt{2}+3-2\sqrt{2}+12\sqrt{2}-3 \\\\\\ 3\sqrt{2}-5\sqrt{2}-2\sqrt{2}+12\sqrt{2}+3-3\implies \stackrel{\textit{adding like-terms}}{8\sqrt{2}}

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The easiest way to draw a straight-line graph, such as this one, is to plot the y-intercept, in this case (0, 490), then plot another point either side of it at a fair distance (for example substitute  = -5 and  = 5 to procure two more sets of co-ordinates). These can be joined up with a straight line to form a section of the graph, which would otherwise extend infinitely either side - use the specified range in the question for x-values, and do not exceed it (clearly here the limit of -values is 0 ≤ x ≤ 735, since neither x nor y can be negative within the context of the question - the upper limit was found by substituting  = 0).

In function notation, the graph is:



The graph of this function represents how the value of the function varies as the value of x varies. Looking back at the question context, this graph specifically represents how many wraps could have been sold at each number of sandwich sales, in order to maintain the same profit of $1470.

When the profit is higher, the gradient is not changed (this is defined by the relationship between the $2 and $3 prices, not the overall profit) - instead the -intercept is higher:






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For example if the two points were (1, 9) and (4, 6):

Δ = 6 - 9 = -3
Δ = 4 - 1 = 3
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I choose the point (4, 6)
6 = (-1 * 4) + c
6 = c - 4
c = 10
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Within the context of the question, I imagine the prices of the two lunch specials will be the same in the third month and hence the gradient will still be  - this means steps 1-6 can be omitted. Furthermore if the axes are clearly labelled, you may even be able to just read off the y-intercept and hence dispose with steps 1-8!
5 0
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Can you tell i'm panicking? ^^"
Archy [21]
ANSWER:
The right option is d)
As 5*1=5
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HOPE IT HELPS!!!!!
PLEASE MARK BRAINLIEST!!!!
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Answer:

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