we know that
The simple interest formula is equal to

where
P is the Principal amount of money to be invested
I is the amount of money in interest
r is the rate of interest
t is Number of Time Periods
in this problem we have

substitute in the formula above and solve for P

![P=14.65/[(0.025)(2)]](https://tex.z-dn.net/?f=P%3D14.65%2F%5B%280.025%29%282%29%5D)

therefore
<u>the answer is</u>

(x)(2)+(x+20)(4)=3502x+4x+80=3506x+80=3506x+80-350=2706x+270/6=45 rate of bus45+20 = rate of train
Choice "A" is the correct answer.
It mentions that it is positively correlated, as stated in the question. Choice D says linearly correlated, so that is incorrect.
I hope this helped you!
Brainliest answer is always appreciated!
Step-by-step explanation:
slope of the segment through (-9, -8) and (-5, 6) is (-9-(-5))/(-8-6)=-(-4)/(-14)=2/7
this means the slope of the perpendicular is -7/2.
the midpoint of the segment is (-7, -1)
so the line is y+1=(-7/2)(x+7).
The required equation of the surface area of the cylinder is 
<u>Solution:</u>
Let "r" be the radius of cylinder and "h" be the height.
Formula for surface area is:

where
is surface of two bases of cylinder and
is surface of mantle.
From the given, the height of the gift box is three times the radius, i.e 
On substituting the given values in the formula we get,
![S = 2\times\pi[(3x+4)^2 + (9x+12)\times(3x+4)]](https://tex.z-dn.net/?f=S%20%3D%202%5Ctimes%5Cpi%5B%283x%2B4%29%5E2%20%2B%20%289x%2B12%29%5Ctimes%283x%2B4%29%5D)
![\Rightarrow S=2\pi[(3x^2)+2\times3x\times4+4^2]+[(9x\times3x)+12\times3x+36x+48]](https://tex.z-dn.net/?f=%5CRightarrow%20S%3D2%5Cpi%5B%283x%5E2%29%2B2%5Ctimes3x%5Ctimes4%2B4%5E2%5D%2B%5B%289x%5Ctimes3x%29%2B12%5Ctimes3x%2B36x%2B48%5D)
![\Rightarrow S=2\pi[9x^2+24x+16]+[21x^2+36x+36x+48]](https://tex.z-dn.net/?f=%5CRightarrow%20S%3D2%5Cpi%5B9x%5E2%2B24x%2B16%5D%2B%5B21x%5E2%2B36x%2B36x%2B48%5D)
![\Rightarrow S=2\pi[9x^2+24x+16+21x^2+72x+48]\rightarrow2\pi[30x^2+96x+64]](https://tex.z-dn.net/?f=%5CRightarrow%20S%3D2%5Cpi%5B9x%5E2%2B24x%2B16%2B21x%5E2%2B72x%2B48%5D%5Crightarrow2%5Cpi%5B30x%5E2%2B96x%2B64%5D)
On multiplying
inside the brackets we get,
![\Rightarrow S=[60\pi x^2+192\pi x+128\pi]](https://tex.z-dn.net/?f=%5CRightarrow%20S%3D%5B60%5Cpi%20x%5E2%2B192%5Cpi%20x%2B128%5Cpi%5D)
Hence, the required equation is 