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Rzqust [24]
3 years ago
7

Did I do it right??? Please respond.

Mathematics
1 answer:
Sedaia [141]3 years ago
8 0

Fraid not.  This time, you did it left.

The tool to use is "Vertical" angles are equal. (They don't add up to 180 degrees.)

3y + 120 = 5y + 100

(you should fill in the missing steps)

y = 10°

The upper/lower pair of vertical angles are both 150°.

.

2x = 6x - 60

(you should fill in the missing steps)

x = 15°

The left/right pair of vertical angles are both 30°.

It's any two angles NEXT TO each other that add up to 180°.

Notice here that (150° + 30°) = 180° .

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Butyric acid ( c3h7cooh) is a weak acid . what is the ph of a 0.0250 m solution of this acid. ka = 1.5 x 10-5 (2 decimal places)
Wewaii [24]

The pH of the weak acid is 3.21

Butyric acid is known as a weak acid, we need the concentration of [H+] formula of weak acid which is given by this equation :

[H^{+}]=\sqrt{Ka . Ma}

where [H+] is the concentration of ion H+, Ka is the weak acid ionization constant, and Ma is the acid concentration.

Since we know the concentration of H+, the pH can be calculated by using

pH = -log[H+]

From question above, we know that :

Ma = 0.0250M

Ka = 1.5 x 10¯⁵

By using the equation, we can determine the concentration of [H+]

[H+] = √(Ka . Ma)

[H+] = √(1.5 x 10¯⁵ . 0.0250)

[H+] = 6.12 x 10¯⁴ M

Substituting the value of [H+] to get the pH

pH = -log[H+]

pH = -log(6.12 x 10¯⁴)

pH = 3.21

Hence, the pH of the weak acid c3h7cooh is 3.21

Find more on pH at: brainly.com/question/14466719

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