Answer:
Pretend the y-axis is a mirror
If the original shape is
P=4,-2
Z=5,-4
M=4,-4
The new image made by mirroring it will be
P’= -4,-2
Z’= -5,-4
M’= -4,-4
Step-by-step explanation:
Sorry if this doesn’t make sense, just graph P’, Z’, and M’ for a mirrored image
Answer:
$44.04
Step-by-step explanation:
14.68 * 3 = 44.04
no entiendo hingles......pero puedo puedo tener esos 5 puntos
Answer:
23. x = 4; DE = 44
24. x = 25; DS = 28
Step-by-step explanation:
23. Point S is the midpoint of DE, so ...
DS = SE
3x +10 = 6x -2
12 = 3x . . . . . . . . . add 2-3x
4 = x . . . . . . . . . . . divide by 3
Then DS has length ...
DS = 3x +10 = 12 +10 = 22
and DE is twice that length, so ...
DE = 44
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24. DS is half the length of DE, so is ...
DS = DE/2 = 56/2
DS = 28
Then x can be found from ...
DS = x +3
28 -3 = x = 25 . . . . . substitute value for DS
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<em>Comment on problem 24</em>
Sometimes it is easier to work parts of a problem out of sequence. Here, finding DS first makes finding x easier.
The area of the square is 81 sq in, and the area of the circule is (3.14)(3 in)^2, or approx 3.14(9) sq in, or approx 28.27 sq in.
Subtract: 81 sq in - 28.27 sq in = approx. 52.73 sq in.
The difference is 52.73 sq in; the square is larger, the circle smaller.
