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fomenos
4 years ago
6

What is s10 for 1 + 2 + 4 + 8+... 256 511 1023 2047

Mathematics
1 answer:
andrew11 [14]4 years ago
8 0

Answer:

1023

Step-by-step explanation:

S_n = \dfrac{a(1 - r^n)}{1 - r}

a = first term

r = common ratio

n = number of terms

Here we have

a = 1

r = 2

n = 10

S_{10} = \dfrac{1(1 - 2^{10})}{1 - 2}

S_{10} = \dfrac{1 - 1024}{-1}

S_{10} = \dfrac{-1023}{-1}

S_{10} = 1023

Of course, since 10 is not such a large number of terms, you can simply do this:

1 + 2 + 4 + 8 + 16 + 32 + 64 + 128 + 256 + 512 = 1023

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Ket [755]

Answer:

y = 1/6x + 5

Step-by-step explanation:

-x + 6y = 30

6y = x + 30

y = 1/6x + 5

6 0
3 years ago
Find the vertex of y=-x^2+6x-12
Debora [2.8K]
You find the x coordinates using x = -b/2a  = -6/2(-1) = 3

Substitute 3 in the equation and find y

y = -(3^2) + 6(3) - 12 = -9 + 18 - 12 = -3

Vertex (3,-3)
8 0
3 years ago
In Miss perrons Class 75% of the students are boys. there are 18 boys in the class what is the total number of students in Miss
Vinvika [58]

Answer:

24 is the total number of students in Miss. Perrons class.

Step-by-step explanation:

you take 18 and divide by 75% (0.75) and you get 24

8 0
3 years ago
Find the Fourier series of f on the given interval. f(x) = 1, ?7 < x < 0 1 + x, 0 ? x < 7
Zolol [24]
f(x)=\begin{cases}1&\text{for }-7

The Fourier series expansion of f(x) is given by

\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi x}7+\sum_{n\ge1}b_n\sin\frac{n\pi x}7

where we have

a_0=\displaystyle\frac17\int_{-7}^7f(x)\,\mathrm dx
a_0=\displaystyle\frac17\left(\int_{-7}^0\mathrm dx+\int_0^7(1+x)\,\mathrm dx\right)
a_0=\dfrac{7+\frac{63}2}7=\dfrac{11}2

The coefficients of the cosine series are

a_n=\displaystyle\frac17\int_{-7}^7f(x)\cos\dfrac{n\pi x}7\,\mathrm dx
a_n=\displaystyle\frac17\left(\int_{-7}^0\cos\frac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\cos\frac{n\pi x}7\,\mathrm dx\right)
a_n=\dfrac{9\sin n\pi}{n\pi}+\dfrac{7\cos n\pi-7}{n^2\pi^2}
a_n=\dfrac{7(-1)^n-7}{n^2\pi^2}

When n is even, the numerator vanishes, so we consider odd n, i.e. n=2k-1 for k\in\mathbb N, leaving us with

a_n=a_{2k-1}=\dfrac{7(-1)-7}{(2k-1)^2\pi^2}=-\dfrac{14}{(2k-1)^2\pi^2}

Meanwhile, the coefficients of the sine series are given by

b_n=\displaystyle\frac17\int_{-7}^7f(x)\sin\dfrac{n\pi x}7\,\mathrm dx
b_n=\displaystyle\frac17\left(\int_{-7}^0\sin\dfrac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\sin\dfrac{n\pi x}7\,\mathrm dx\right)
b_n=-\dfrac{7\cos n\pi}{n\pi}+\dfrac{7\sin n\pi}{n^2\pi^2}
b_n=\dfrac{7(-1)^{n+1}}{n\pi}

So the Fourier series expansion for f(x) is

f(x)\sim\dfrac{11}4-\dfrac{14}{\pi^2}\displaystyle\sum_{n\ge1}\frac1{(2n-1)^2}\cos\frac{(2n-1)\pi x}7+\frac7\pi\sum_{n\ge1}\frac{(-1)^{n+1}}n\sin\frac{n\pi x}7
3 0
3 years ago
Please help I don’t understand it’s like angles and stuff picture above. 20 POINTS WILK MARK BRAINLEST FOR RIGHT ANSWERS ONLY
oksano4ka [1.4K]

Since 6x - 44 and 88 degrees are the same (exterior angles), we can start off with the first equation, 6x - 44 = 88

6x - 44 = 88

    +44    +44

6x      =   132

÷6         ÷6

x  = 22

same with the second problem (exterior angles are equal):

equation:

15x + 6 = 9x + 54

       -6              -6

15x    = 9x + 48

-9x      -9x

6x   =    48

÷6         ÷6

x   =   8

Hope this helped! :D

5 0
3 years ago
Read 2 more answers
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