Firstly , we will check continuity at x=1
we can use method
Suppose, f(x) is continuous at x=c
then it must satisfy
firstly , we can find limit
so, we get
now, we can find f(1)
so, we got
so, this is continuous at x=1
Hence , option-D...........................Answer
The absolute value of -5 five would be five because no absolute value is going to be negative since its turning a number to a negative. so the correct answer is |5| = 5
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Since they are between the parallel lines they are "alternate INTERIOR angles".
Answer:
Step-by-step explanation:
Number of vertices
3
Variable constraints
a>0 and b>0
Diagonal lengths
(data not available)
Height
b
Area
A = (a b)/2
Centroid
x^_ = (a/3, b/3)
Mechanical properties:
Area moment of inertia about the x-axis
J_x invisible comma x = (a b^3)/12
Area moment of inertia about the y-axis
J_y invisible comma y = (a^3 b)/12
Polar moment of inertia
J_zz = 1/12 a b (a^2 + b^2)
Product moment of inertia
J_x invisible comma y = -1/24 a^2 b^2
Radii of gyration about coordinate axes
r_x = b/sqrt(6)
r_y = a/sqrt(6)
Distance properties:
Side lengths
a | sqrt(a^2 + b^2) | b
Hypotenuse
sqrt(a^2 + b^2)
Perimeter
p = sqrt(a^2 + b^2) + a + b
Inradius
r = 1/2 (-sqrt(a^2 + b^2) + a + b)
Circumradius
R = 1/2 sqrt(a^2 + b^2)
Generalized diameter
sqrt(a^2 + b^2)
Convexity coefficient
χ = 1
Mean triangle area
A^_ = (a b)/24
When 10 by anything you just write the amount of 0 so if it was 10^12 i would write 12 0s so 10^6 1,000,000
