What are the option? If there are none
then you would take the two fractions and multiply the <span>denominators thus making a new fractions. This is called finding the common denominator.
</span>Ex: 1/2 and 2/3 would have a CD of 6.
<span>So, you would rename them 3/6 and 4/6</span>
To find the cost of 1 water bottle you divide 60 degrees into 75 (75/60) which gives you 1.25 degrees for each water bottle. To find 120 water bottles temperature multiply the 1.25 degrees for 1 water bottle times 120 (120x1.25). 120x1.25=150 The answer would be 150degrees
Answer:
x1, x2 = 7.73 , 4.27
Step-by-step explanation:
To find the roots of a quadratic function we have to use the bhaskara formula
ax^2 + bx + c
x^2 - 12x + 33
a = 1 b = -12 c = 33
x1 = (-b + √ b^2 - 4ac)/2a
x2 =(-b - √ b^2 - 4ac)/2a
x1 = (12 + √(-12^2 - (4 * 1 * 33))) / 2 * 1
x1 = (12 + √(144 - 132)) / 2
x1 = (12 + √12) / 2
x1 = (12 + 3.46) / 2
x1 = 15.46 / 2
x1 = 7.73
x2 = (12 - √(-12^2 - (4 * 1 * 33))) / 2 * 1
x2 = (12 - √(144 - 132)) / 2
x2 = (12 - √12) / 2
x2 = (12 - 3.46) / 2
x2 = 8.54 / 2
x2 = 4.27
The second one is but i’m so so sure
Answer:
The probability that a call last between 4.2 and 4.9 minutes is 0.4599
Step-by-step explanation:
Let X be the length in minutes of a random phone call. X is a normal distribution with mean λ=4.2 and standard deviation σ=0.4. We want to know P(4.2 < X < 4.9). In order to make computations, we will use W, the standarization of X, given by the following formula
![W = \frac{X-\mu}{\sigma} = \frac{X-4.2}{0.4}](https://tex.z-dn.net/?f=%20W%20%3D%20%5Cfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%20%3D%20%5Cfrac%7BX-4.2%7D%7B0.4%7D%20)
We will use
, the cummulative distribution function of W. The values of
are well known and the can be found in the attached file
![P(4.2 < X < 4.9) = P(\frac{4.2-4.2}{0.4} < \frac{X-4.2}{0.4} < \frac{4.9-4.2}{0.4}) = P(0 < W < 1.75) = \\ \phi(1.75) - \phi(0) = 0.9599-0.5 = 0.4599](https://tex.z-dn.net/?f=P%284.2%20%3C%20X%20%3C%204.9%29%20%3D%20P%28%5Cfrac%7B4.2-4.2%7D%7B0.4%7D%20%3C%20%5Cfrac%7BX-4.2%7D%7B0.4%7D%20%3C%20%5Cfrac%7B4.9-4.2%7D%7B0.4%7D%29%20%3D%20P%280%20%3C%20W%20%3C%201.75%29%20%3D%20%5C%5C%20%5Cphi%281.75%29%20-%20%5Cphi%280%29%20%3D%200.9599-0.5%20%3D%200.4599)
We conclude that the probability that a call last between 4.2 and 4.9 minutes is 0.4599