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Gelneren [198K]
3 years ago
6

All that is left in a packet of candy are 7 reds, 4 greens, and 2 blues, What is the probability that a random drawing yields a

green followed by a red assuming that the first candy drawn is put back into the packet? 
Mathematics
2 answers:
kifflom [539]3 years ago
7 0
Multiply 7(reds) by 4 (greens) to get 2/13
Inessa [10]3 years ago
4 0
Probability of drawing a green = 4/13
Probability of drawing a red = 2/13
probability of drawing a green and then a red is 4/13 * 2/13 = 6/169 
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Greeley [361]

Answer:

Due to the higher z-score, Jane did better in class.

Step-by-step explanation:

Z-score:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

Whoever's grade had the better z-score did better in class.

Mary's:

Mean of 85, standard deviation of 5, grade of 88. This means that \mu = 85, \sigma = 5, X = 88. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{88 - 85}{5}

Z = 0.6

Jane's

Mean of 80, standard deviation of 10, grade of 88. This means that \mu = 80, \sigma = 10, X = 88. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{88 - 80}{10}

Z = 0.8

Due to the higher z-score, Jane did better in class.

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2 years ago
Can anyone solve this problem please help me
LUCKY_DIMON [66]
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