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Gelneren [198K]
3 years ago
6

All that is left in a packet of candy are 7 reds, 4 greens, and 2 blues, What is the probability that a random drawing yields a

green followed by a red assuming that the first candy drawn is put back into the packet? 
Mathematics
2 answers:
kifflom [539]3 years ago
7 0
Multiply 7(reds) by 4 (greens) to get 2/13
Inessa [10]3 years ago
4 0
Probability of drawing a green = 4/13
Probability of drawing a red = 2/13
probability of drawing a green and then a red is 4/13 * 2/13 = 6/169 
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