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Gelneren [198K]

3 years ago

6

All that is left in a packet of candy are 7 reds, 4 greens, and 2 blues, What is the probability that a random drawing yields a

green followed by a red assuming that the first candy drawn is put back into the packet?

2 answers:

kifflom [539]3 years ago

7 0

Multiply 7(reds) by 4 (greens) to get 2/13

Inessa [10]3 years ago

4 0

Probability of drawing a green = 4/13
Probability of drawing a red = 2/13
probability of drawing a green and then a red is 4/13 * 2/13 = 6/169

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in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference

allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

$\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}$

so that

$a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d$

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$21=(n-1)d$

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Case 1: $n-1=1$ and $d=21$ . But

$\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123$

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$\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123$

Case 3: $n-1=3$ and $d=7$ . But

$\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123$

Case 4: $n-1=7$ and $d=3$ . But

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3 years ago

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3 years ago

Write the radical in simplest radical form<br><br><br><br> √5/8

tiny-mole [99]

Answer:

$\dfrac{\sqrt{10}}{4}$

Step-by-step explanation:

$\sqrt{\dfrac{5}{8}} =$

$= \dfrac{\sqrt{5}}{\sqrt{8}}$

$= \dfrac{\sqrt{5}}{\sqrt{4 \times 2}}$

$= \dfrac{\sqrt{5}}{2 \sqrt{2}}$

$= \dfrac{\sqrt{5}\sqrt{2}}{2 \sqrt{2}\sqrt{2}}$

$= \dfrac{\sqrt{10}}{2 \times 2}$

$= \dfrac{\sqrt{10}}{4}$

3 0

3 years ago