I.) (5x+3)/4-(2x-4)/3=5
Clear fractions:
3·((5x+3)/4)=15x+9
4·((2x-4)/3)=8x-16
15x+9-(8x-16)=5
15x+9-8x+16=5
Combine like terms:
7x+25=5
7x=-20
x=-20/7
II.) (3/11)·(5/6)-(9/12)·(4/3)+(5/13)·(6/15)
Remember PEMDAS
So first multiply:
3/11·5/6=15/66
9/12·4/3=3/3·1/1=3/3=1
5/13·6/15=1/13·6/3=6/39=2/13
(15/66)-1+(2/13)
Combine:
15/66-1/1=15/66-66/66=-51/66
-51/66+2/3=-51/66+44/66=-7/66
Answer: -7/66 :)
You're given two angles and the side not between them are congruent, so the AAS theorem applies. (2nd selection)
Answer:
b = - 5
Step-by-step explanation:
(k + a )(k + x) + 1 = k^2 + kx + ak + ax + 1
I think the way to solve this is to worry about the 36
k^s + 1 + ak should equal 36
We know that a = 2
k^2 + 1 + 2k = 36
k^2 + 2k + 1 - 36 = 0
k^2 + 2k - 35 = 0
(k + 7)(k - 5) = 0
k = -7 is the only acceptable answer. It is given that K < 0.
bx = kx + ax
b = k + a
b = - 7 + 2
b = - 5
Answer:
C
Step-by-step explanation:
Answer:
2 Significant Figures
Step-by-step explanation:
The A and the .
