All categories

3 years ago

Which graph is correct

Mathematics

1 answer:

GrogVix [38]3 years ago

8 0

Answer:

Step-by-step explanation:

Taking the absolute value of anything makes it positive, so you know that the graph of |f(x)| must only have positive.

And since c is the only graph with no negative values c it must be the answer

Also if you compare it with f(x), c it flips the negative parts of f(x) to positive.

You might be interested in

A company makes 140 bags.

malfutka [58]

Answer:

Step-by-step explanation:

The question says we have 140 bags and we have 4 models

bags have buttons but no zips.

bags have zips but no buttons.

bags have neither zips nor buttons

bags have both zips and buttons

We don't know how many bags have zips and buttons but we know how many bags are produced. And other 3 types of bags number. So we can calculate

140-47-48-22=23

That means we have 23 bags that have zips and buttons

and

48 of the bags have zips too. that means we have 48+23=71 bags that have zips on them.

8 0

2 years ago

Pls help i give you brainliest

stepladder [879]

Kimi no toriko ni natte ti shi mae ba kitto

7 0

3 years ago

Integration of ∫(cos3x+3sinx)dx

Murljashka [212]

Answer:

$\boxed{\pink{\tt I = \dfrac{1}{3}sin(3x) - 3cos(x) + C}}$

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

$\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\ dx$

Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
Now , Rewrite using du and u .

$\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I = \dfrac{1}{3}sin(3x) - 3cos(x) + C }}}}}$

6 0

3 years ago

If you wanted to find the mean height of students in an elementary school,

Kryger [21]

It is not possible to select a single group from the primary school, since being a single group it could not in any way represent the entire primary school.

Choosing a group would provide the average height for that group, not the entire primary.

Assumptions can be made that the course of half of the primary would theoretically give us a more accurate representation, but the objective is to select a number of students from each course and there would be a representative sample of the entire primary.

6 0

3 years ago

Peter decides to invest $1,200,000 in a period annuity that earns 4.6% APR compounded monthly for a period of 20 years. How much

ad-work [718]

Given is the Present Value of annuity, PV = 1,200,000 dollars.

Given that 4.6% APR compounded monthly i.e. r = 4.6%/12 = 0.003833

Given that 20 years of investment i.e. N = 20x12 = 240

It says to find monthly income from the annuity.

We know the formula for Periodic Payment (when PV is known) is given as follows :-

$Periodic \;payment = \frac{PV}{\frac{1-\frac{1}{(1+r)^{N}}}{r}} \\\\Periodic \;payment = \frac{1,200,000}{\frac{1-\frac{1}{(1+0.003833)^{240}}}{0.003833}} \\\\Periodic \;payment = \frac{1,200,000}{\frac{1-\frac{1}{(1.003833)^{240}}}{0.003833}} \\\\Periodic \;payment = \frac{1,200,000}{\frac{1-\frac{1}{2.504681211}}{0.003833}} \\\\Periodic \;payment = \frac{1,200,000}{\frac{1-0.399252406}{0.003833}} \\\\Periodic \;payment = \frac{1,200,000}{\frac{0.600747594}{0.003833}}$

$Periodic \;payment = \frac{1,200,000}{156.7303924} \\\\Periodic \;payment = 7656.460128 \\\\Periodic \;payment = 7656.46 \;dollars \;per \;month$

Hence, Monthly Income would be 7,656.46 dollars.

8 0

3 years ago

Read 2 more answers