3 years ago

How to write this proof?

Mathematics

1 answer:

bogdanovich [222]3 years ago

3 0

pls mark as brainliest

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I am a two digit square number. the sum of my digits is 13. what Square number am I

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49 Because 7x7 is 49 & 4+9=13

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Which equation represents the data shown in the table below? Fence Length (y) 100 150 180 240 Number of Posts (x) 11 16 19 25 A

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Answer:y=10x-1

Step-by-step explanation:

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3 years ago

The expression 16-3/4 is equivalent to the expression

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Chemists use pH as a measure of acidity or alkalinity of a solution. It uses the concentration of hydrogen ions H+ in a logarith

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Answer:

$g(f(d)) = -dlog_{10}(0.5 * 10^{-4})$

Step-by-step explanation:

Given

$f(d) = (0.5 * 10^{-4})^d$

$g(H+) = -log_{10}(H+)$

Required

Find the composite function g(f(d))

We have:

$g(H+) = -log_{10}(H+)$

Substitute f(d) for H+

$g(f(d)) = -log_{10}(f(d))$

Substitute $f(d) = (0.5 * 10^{-4})^d$

$g(f(d)) = -log_{10}((0.5 * 10^{-4})^d)$

Apply law of logarithm

$g(f(d)) = -dlog_{10}(0.5 * 10^{-4})$

Hence, the function is:

$g(f(d)) = -dlog_{10}(0.5 * 10^{-4})$

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3 years ago

Read 2 more answers

Find a degree 3 polynomial with real coefficients having zeros 2 and 2 − 2 i and a lead coefficient of 1. Write P in expanded fo

Zanzabum

Answer:

The polynomial with real coefficients having zeros 2 and 2 - 2i is

x³ - 6x² + 16x - 16 = 0

Step-by-step explanation:

Given that a polynomial has zeros at 2 and 2 - 2i, we want to write this polynomial.

We have

x - 2 = 0

x - (2 - 2i) = 0

=> x - 2 + 2i = 0

Since the polynomial has real coefficients, and 2 - 2i is a zero of the polynomial, the conjugate of 2 - 2i, which is 2 + 2i is also a polynomial.

x - (2 + 2i) = 0

=> x - 2 - 2i = 0

Now,

P(x) = (x - 2)(x - 2 + 2i)(x - 2 - 2i) = 0

= (x - 2)((x - 2)² - (2i)²) = 0

= (x - 2)(x² - 4x + 8) = 0

= x³ - 4x² + 8x - 2x² + 8x - 16 = 0

= x³ - 6x² + 16x - 16 = 0

This is the polynomial required.

6 0

3 years ago