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nikitadnepr [17]

3 years ago

10

1102 divided by 58.

1 answer:

Fynjy0 [20]3 years ago

3 0

1102 divided by 58 equals 19

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Abargain clothing store is selling 5 shirts for $20.

Rainbow [258]

Answer: Both of their statements are true. Explanation: If you can buy 5 shirts for $20, that means the unit price would be $4 per shirt. (to find the unit price just divide the cost by the quantity) So, it is true that you can buy one shirt for $4 and 2 shirts for $8. Hopefully this helps.

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Clara would like to buy a toy for her baby sister that sells for

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Connie started with___<br> in her saving account<br><br><br> Fill in the blank

Irina18 [472]

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Connie started with <u>$25</u> in her savings account.

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3 years ago

Read 2 more answers

Simplify<br><br>Square root of 50 over 2 times -4 + square root of 121

kobusy [5.1K]

Answer:

-9

Step-by-step explanation:

$\sqrt{\dfrac{50}{2}}\cdot(-4)+\sqrt{121}=-4\sqrt{25}+11=-4\cdot5+11\\\\=-20+11=\boxed{-9}$

Your calculator can help with this.

4 0

2 years ago

A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station. Find the ra

Anika [276]

Answer:

The rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.

Step-by-step explanation:

Given information:

A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station.

$z=1$

$\frac{dx}{dt}=430$

We need to find the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station.

$y=2$

According to Pythagoras

$hypotenuse^2=base^2+perpendicular^2$

$y^2=x^2+1^2$

$y^2=x^2+1$ .... (1)

Put z=1 and y=2, to find the value of x.

$2^2=x^2+1^2$

$4=x^2+1$

$4-1=x^2$

$3=x^2$

Taking square root both sides.

$\sqrt{3}=x$

Differentiate equation (1) with respect to t.

$2y\frac{dy}{dt}=2x\frac{dx}{dt}+0$

Divide both sides by 2.

$y\frac{dy}{dt}=x\frac{dx}{dt}$

Put $x=\sqrt{3}$ , y=2, $\frac{dx}{dt}=430$ in the above equation.

$2\frac{dy}{dt}=\sqrt{3}(430)$

Divide both sides by 2.

$\frac{dy}{dt}=\frac{\sqrt{3}(430)}{2}$

$\frac{dy}{dt}=372.390923627$

$\frac{dy}{dt}\approx 372$

Therefore the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.

6 0

4 years ago