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lesya692 [45]
3 years ago
9

The prism has a volume up to 150.find the length of the prism

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
5 0

Step-by-step explanation:

We have to know that in order to solve for the volume of a rectangular prism, we have to use this formula: l * w * h. This stands for length multiplied by width multiplied by height.

<u>Step 1</u>

Let's look at the numbers we already have. The height of the prism is 4 feet and the width is 5 feet. When we multiply them together, we got 20 feet.

<u>Step 2</u>

The volume of this prism adds up to 150 square feet. To find the length of this prism, we have to divide 150 by 20.

150 / 20=7.5

Our final answer: l = 7.5 feet

We can check our answer by multiplying all the numbers together.

4 * 5* 7.5 = 150

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What is the value of x?<br> x = [ ? ]
Mnenie [13.5K]

Answer:

Step-by-step explanation:

The tangent to the angle makes an angle of 90° with the radius.

The interior angle of the equilateral triangle is 60, so that leaves 90-60 = 30° for the remaining angle with the tangent.

By the exterior angle theorem, 30°+x° = 60° (interior angle of the equilateral triangle), therefore

x = 60-30 = 30°.

4 0
3 years ago
Read 2 more answers
You and your friend are comparing two loan options for a $165,000 house. Loan 1 is a 15-year loan with an annual interest rate o
Harlamova29_29 [7]

Answer:

No, he is wrong.

Step-by-step explanation:

Since, the total payment of a loan after t years,

A=P(1+r)^t

Where,

P = present value of the loan,

r = rate per period ,

n = number of periods,

Given,

P = $165,000,

In loan 1 :

r = 3% = 0.03, t = 15 years,

So, the total payment of the loan is,

A_1 = 165000(1+0.03)^{15}=165000(1.03)^{15}\approx \$ 257,064.62

In loan 2 :

r = 4% = 0.04, t = 30 years,

So, the total payment of the loan is,

A_2 = 165000(1+0.04)^{30}=165000(1.04)^{30}\approx \$ 535,160.59

Since, A_1 < A_2

Hence, total amount repaid over the loan will be less for Loan 1.

That is, the friend is wrong.

7 0
2 years ago
Someone help with this
elena-14-01-66 [18.8K]

The quadrants are I, II, III, and IV, (meaning 1, 2, 3, and 4). The first quadrant is in the upper right, which has both positive x and positive y values. The second quadrant is the upper left, which has negative x and positive y values. The third quadrant is the lower left, which has both negative x and y values. The fourth quadrant is the lower right, which has positive x and negative y values. Using this knowledge and our positive and negative signs, the following are the answers to questions 1-6.

1) (-4, -2) - Quadrant III, both x and y are negative

2) (0, -7) - This point is actually on the y-axis. The x value is 0 and the y value is -7, so the graph is 7 units down from the origin on the y-axis.

3) (0,0) - This point is the origin, or where the x and y axes cross (the middle of the graph).

4) (6, -9) - This point is in Quadrant IV, because it has a positive x value and a negative y value

5) (3,5) - This point is in Quadrant I, because both the x and y values are positive.

6) (8,0) - This point is on the x-axis. The y-value is zero, so this point is 8 units to the right of the origin between Quadrant I and Quadrant IV.

Using the knowledge presented above, to graph the points given to you in the second part of the problem, first you can figure out what quadrant or part of the graph the point is on. Then, you can count the number of units (squares on the graph) in the right direction (remember that up is positive on the y-axis and down is negative, and to the right is positive on the x-axis and to the left is negative) in order to plot the points. Then, you must connect the points that correspond to the same figure in order to create the figures.

Please comment if you have any questions!

Hope this helps!

7 0
3 years ago
Need help! ASAP! With algebra
dimaraw [331]

Answer:

2;4;3

Step-by-step explanation:

y=2x²+4x+3

4 0
2 years ago
Please help I think these are the right answers!!!
Papessa [141]

We performed the following operations:

f(x)=\sqrt[3]{x}\mapsto g(x)=2\sqrt[3]{x}=2f(x)

If you multiply the parent function by a constant, you get a vertical stretch if the constant is greater than 1, a vertical compression if the constant is between 0 and 1. In this case the constant is 2, so we have a vertical stretch.

g(x)=2\sqrt[3]{x}\mapsto h(x)=-2\sqrt[3]{x}=-g(x)

If you change the sign of a function, you reflect its graph across the x axis.

h(x)=-2\sqrt[3]{x}\mapsto m(x)=-2\sqrt[3]{x}-1=h(x)-1

If you add a constant to a function, you translate its graph vertically. If the constant is positive, you translate upwards, otherwise you translate downwards. In this case, the constant is -1, so you translate 1 unit down.

5 0
3 years ago
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