What is probability rolling a number greater than 4?
The only numbers there are is 5 and 6.
That means that there are 2 outcomes out of 6 total outcomes.
That would be 2/6.
Divide the the top and bottom by 2.
In simplest form it would be 1/3.
2/6=1/3
The answer is 1/3. The probability of throwing a number greater than 4 is 1/3.
Answer:
1.16
Step-by-step explanation:
Given that;
For some positive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770.
This implies that:
P(0<Z<z) = 0.3770
P(Z < z)-P(Z < 0) = 0.3770
P(Z < z) = 0.3770 + P(Z < 0)
From the standard normal tables , P(Z < 0) =0.5
P(Z < z) = 0.3770 + 0.5
P(Z < z) = 0.877
SO to determine the value of z for which it is equal to 0.877, we look at the
table of standard normal distribution and locate the probability value of 0.8770. we advance to the left until the first column is reached, we see that the value was 1.1. similarly, we did the same in the upward direction until the top row is reached, the value was 0.06. The intersection of the row and column values gives the area to the two tail of z. (i.e 1.1 + 0.06 =1.16)
therefore, P(Z ≤ 1.16 ) = 0.877
Answer:
10/1
Step-by-step explanation:
You do
6÷ 3/5
Flip the 3/5 then multiply
6 ° 5/3
Reduce the numbers with the greatest common factor 3
So 2•5
And that's 10
Equation Form:
x
=
12
,
y
=
50
3
or
x
=
12
,
y
=
50
3
x
=
12
,
y
=
50
3
x
=
12
,
y
=
50
3
x
=
12
,
y
=
50
3
Step-by-step explanation: I have no idea why it looks like that
