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3 years ago

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Suppose a shipment of 400 components contains 68 defective and 332 non-defective computer components. From the shipment you take

a random sample of 25. When sampling with replacement (so that the p = probability of success does not change), note that a success in this case is selecting a defective part. The mean of this situation is?

1 answer:

MrRissso [65]3 years ago

6 0

Answer:

mean (μ) = 4.25

Step-by-step explanation:

Let p = probability of a defective computer components = $\frac{68}{400} = 0.17$

let q = probability of a non-defective computer components = $\frac{332}{400} = 0.83$

Given random sample n = 25

we will find mean value in binomial distribution

The mean of binomial distribution = np

here 'n' is sample size and 'p' is defective components

mean (μ) = 25 X 0.17 = 4.25

<u>Conclusion</u>:-

mean (μ) = 4.25

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On his outward journey, Ali travelled at a speed of s km/h for 2.5 hours. On his return journey, he increased his speed by 4 km/

den301095 [7]

Answer:

3.08 km/h.

Step-by-step explanation:

We know that,

$Speed=\dfrac{Distance}{Time}$

Ali traveled at a speed of s km/h for 2.5 hours.

Let d be the distance and t be the time.

$2.5=\dfrac{d}{t}$

$2.5t=d$ ...(1)

On his return journey, he increased his speed by 4 km/h and saved 15 minutes. So, distance is d and times is t-15.

$4=\dfrac{d}{t-15}$

$4(t-15)=d$ ...(2)

From (1) and (2), we get

$4(t-15)=2.5t$

$4t-60-2.5t=0$

$1.5t=60$

$t=40$

Put t=40 in (1).

$d=2.5(40)=100$

So, t=40 and d=100.

Now,

Total distance = d + d = 100 + 100 = 200

Total time = t + t - 15 = 40 + 40 - 15 = 65

So, the average speed is

$\text{Average speed}=\dfrac{\text{Total distance}}{\text{Total time}}$

$\text{Average speed}=\dfrac{200}{65}$

$\text{Average speed}\approx 3.08$

Therefore, the average speed is 3.08 km/h.

3 0

3 years ago

) One year, professional sports players salaries averaged $1.5 million with a standard deviation of $0.9 million. Suppose a samp

Nutka1998 [239]

Answer:

Probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.

Step-by-step explanation:

We are given that one year, professional sports players salaries averaged $1.5 million with a standard deviation of $0.9 million.

Suppose a sample of 400 major league players was taken.

<em>Let </em> $\bar X$ <em> = sample average salary</em>

The z-score probability distribution for sample mean is given by;

Z = $\frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} }$ ~ N(0,1)

where, $\mu$ = mean salary = $1.5 million

$\sigma$ = standard deviation = $0.9 million

n = sample of players = 400

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the average salary of the 400 players exceeded $1.1 million is given by = P( $\bar X$ > $1.1 million)

P( $\bar X$ > $1.1 million) = P( $\frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} }$ > $\frac{ 1.1-1.5}{{\frac{0.9}{\sqrt{400} } }} }$ ) = P(Z > -8.89) = P(Z < 8.89)

<em>Now, in the z table the maximum value of which probability area is given is for critical value of x = 4.40 as 0.99999. So, we can assume that the above probability also has an area of 0.99999 or nearly close to 1.</em>

Therefore, probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.

4 0

2 years ago

The partial blueprint of a house that includes 3 bedrooms is shown below. The scale is 2.75 inches : 3 feet. What is the actual

nordsb [41]

The partial blueprint of a house that includes 3 bedrooms is shown below. The scale is 2.75 inches : 3 feet. What is the actual length and width of Bedroom 3 in feet?

Bedroom 1 w=9.17; l= 11 in

Bedroom 2 w=7.33 in; l= 12.83

Bedroom 3 w= 11 in; l= 14.67 in

______________________________________

___________

2.75 inches : 3 or 2.75 in / 3 feet

________________

Can you see the updates?

______________

Bedroom 3 w= 11 in; l= 14.67 in

11 in * 3 feet / 2.75 in = 12 feet

14.67 in 3 feet / 2.75 in = 16 feet

_________________________

Answer

Bedroom 3 w= 12 ft ; l= 16 ft

3 0

1 year ago

Jacob spent 3 hours skiing and snowboarding. He skied for 1 hours 25 minutes. How long did he spend snowboarding?

lord [1]

Answer:

Hours spent for snowboarding = 1 hour 35 minutes

Step-by-step explanation:

Total hours spent for skiing and snowboarding = 3 hours

Hours spent for skiing = 1 hours 25 minutes

How long did he spend snowboarding?

Hours spent for snowboarding = Total hours spent for skiing and snowboarding - Hours spent for skiing = 1 hours 25 minutes

= 3 hours - 1 hours 25 minutes

1 hour = 60 minutes

3 hours = 180 minutes

1 hours 25 minutes = 85 minutes

3 hours - 1 hours 25 minutes

= 180 minutes - 85 minutes

= 95 minutes

95 minutes = 1 hour 35 minutes

Hours spent for snowboarding = 1 hour 35 minutes

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2 years ago

yvette earned $66.00 for 8 hours of work. lizbeth earned $68.80 working the same amount of time. how much more per hour did lizb

sergeinik [125]

The answer is lizeth earns 0.35 cents more per hour. beacuse 66 divided by 8 =8.25 then 68.80 divided by 8 is 8.60 then if you subtract 8.60-8.25 it equals 0.35

8 0

2 years ago

Read 2 more answers