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3 years ago

To convert 2.6 hours into seconds which two ratios could you multiply by?

1 answer:

3 0

One hour is composed of 60 minutes and each minute has 60 seconds. Hence,
1 hr x (60 min / 1 hr) x (60 s/ 1 hr) = 3600 seconds
Each hour has 3600 seconds. To convert the given,
2.6 hours x (3600 s/ 1 hr) = 9360 seconds
Therefore, 2.6 hours is also equal to 9360 seconds.

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JoAnn works in a publicity office at the state university. She is paid

sleet_krkn [62]

JoAnn works 43 hrs week.

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3 years ago

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Find the area of the semicircle need help asapp

sergij07 [2.7K]

Answer:

2 pi

Step-by-step explanation:

The radius is 2

The area of a circle is

A = pi r^2

We have 1/2 of a circle so

1/2 A = 1/2 pi r^2

=1/2 pi ( 2)^2

=1/2 pi *4

= 2 pi

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3 years ago

Wendy is paid $12 per hour and plans to work between 30 and 35 hours per week. Identify the independent and dependent quantity i

UNO [17]

The independent quantity is her pay and the dependent quantity is the hours she works in a week.
I believe the range would be 30 to 35 hours and the domain would be $360 to $450.

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3 years ago

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A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

3 years ago

Which function is the inverse of y = 1/4x^2 - 1, where x < 0

kykrilka [37]

Answer:

Step-by-step explanation:

25 x 25= 625

625-1= 624

B= y= -(200 + 1) which to the square root = 625

5 0

3 years ago