(8q)/4 ..................
Answer:

Step-by-step explanation:
The question is as following:
The verticies of a triangle on the coordinate plane are
A(0, 0), B(2, 0) and C(0, 2).
What would be the coordinates of triangle A'B'C' if triangle ABC was dilated by a factor of 1/3 ?
=============================================
Given: the vertices of a triangle ABC are A(0, 0), B(2, 0) and C(0, 2).
IF the triangle is dilated by a factor of k about the origin, then
(x,y) → (kx , ky)
that triangle ABC was dilated by a factor of 1/3 to create the triangle A'B'C'.
It is given that triangle ABC was dilated by a factor of 1/3 to create the triangle A'B'C'.
If a figure dilated by a factor of 1/3 about the origin
So, 
<u>So, The coordinates of the triangle A'B'C' are:</u>

Answer:


Step-by-step explanation:
Given


See attachment for both functions
Solving (a): Which is greater in A(4) and B(4).
From the readings of the graph


By comparison:
because 
Solving (b): When is A(t) = B(t)
From the readings of the graph
when 
i.e.

A) For both sets A and B, calculating the mean, range, and quartiles are a good way of measuring the center and spread. Using standard deviation may not be the best because we do not know whether the distributions are normal or not.
b) For set A, the lowest value is 63, while the highest is 86. An estimate for the mean, based on the average of these, is 74.5. Most of the 70+ values are below 74.5, so we may guess that the mean will be above the median.
For set B, the lowest is 63, while the maximum is 95. The estimated mean would be 79. But since there are more values on the 80+ and 90+ side, the median is likely to be higher than 79.
c) For set A, the mean is 74.79, while the median is 73, therefore the mean is above the median, and the prediction in part b is correct.
Answer:
Hypotenuse = 11.4 cm
Step-by-step explanation:
Hypotenuse ² = opposite ² + adjacent ²
Opposite = 7 cm
Adjacent = 9 cm
Hypotenuse ² = opposite ² + adjacent ²
= 7² + 9²
= 49 + 81
Hypotenuse ² = 130
Hypotenuse = √130
= 11.40
Hypotenuse = 11.4 cm