56 miles per hour
15 minutes is 1/4 of an hour
1/4 = 0.25
so 56 x 4.25 = 238 miles
X(force put on box)>40
In order to move the box you have to apply more force than the box has when it’s not moving.
Answer:
3x−1
Step-by-step explanation:
1 Split the second term in 6{x}^{2}+x-16x
2
+x−1 into two terms.
\frac{6{x}^{2}+3x-2x-1}{4{x}^{2}-1}
4x
2
−1
6x
2
+3x−2x−1
2 Factor out common terms in the first two terms, then in the last two terms.
\frac{3x(2x+1)-(2x+1)}{4{x}^{2}-1}
4x
2
−1
3x(2x+1)−(2x+1)
3 Factor out the common term 2x+12x+1.
\frac{(2x+1)(3x-1)}{4{x}^{2}-1}
4x
2
−1
(2x+1)(3x−1)
4 Rewrite 4{x}^{2}-14x
2
−1 in the form {a}^{2}-{b}^{2}a
2
−b
2
, where a=2xa=2x and b=1b=1.
\frac{(2x+1)(3x-1)}{{(2x)}^{2}-{1}^{2}}
(2x)
2
−1
2
(2x+1)(3x−1)
5 Use Difference of Squares: {a}^{2}-{b}^{2}=(a+b)(a-b)a
2
−b
2
=(a+b)(a−b).
\frac{(2x+1)(3x-1)}{(2x+1)(2x-1)}
(2x+1)(2x−1)
(2x+1)(3x−1)
6 Cancel 2x+12x+1.
\frac{3x-1}{2x-1}
2x−1
3x−1
Answer: x = 4
Step-by-step explanation:
4x = 13 + 3
4x = 16
x = 16/4
x = 4
Let us call them a, b and c
we know that
a+1=b
a+2=c
a+2b=12+c
we can deduce the following:
a+2(a+1)=12+(a+2)
3a+2=a+14
2a=12
a=6
so b would be 7 and c would be 8
Makes sense ?