Factorise the following expressions a. p^2+6p+8
2 answers:
Answer:
(p+4)(p+2)
Step-by-step explanation:
First because there is a p² we can put that in the brackets already.
<h3>(p )(p )</h3><h3 />
Then we need to find numbers that times together to give 8
<h3>8 4×2 8×1 </h3>
So we only need one of these two pairs and to decide that we need to see which one adds/subtracts to form 6 (in the middle).
<h3>4-2=2 which is wrong</h3><h3>4+2=6 which is correct</h3>
So 4 and 2 would go in the gaps:
<h3>(p+4)(p+2)</h3>
Answer:
(p+2)(p+4)
Step-by-step explanation:
Factor p2+6p+8
p2+6p+8
=(p+2)(p+4)
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<span>i think its the outcomes do not appear to be equally likely, so a uniform probability model is not a good model to represent probabilities in Tessa's experiment.<span> </span></span>