So since you know that x^2-1 is equal to (x-1)(x+1),
you can figure that this factors to
(y^2-x^3)(y^2+x^3)
because you know how the difference of two squares formula, stated on the top line of this answer.
Answer:
1. S(1) = 1; S(n) = S(n-1) +n^2
2. see attached
3. neither
Step-by-step explanation:
1. The first step shows 1 square, so the first part of the recursive definition is ...
S(1) = 1
Each successive step has n^2 squares added to the number in the previous step. So, that part of the recursive definition is ...
S(n) = S(n-1) +n^2
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2. See the attachment for a graph.
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3. The recursive relation for an arithmetic function is of the form ...
S(n) = S(n-1) +k . . . . . for k = some constant
The recursive relation for a geometric function is of the form ...
S(n) = k·S(n-1) . . . . . . for k = some constant
The above recursive relation is not in either of these forms, so it is neither geometric nor arithmetic.
Answer:
The photo below
Step-by-step explanation:
I hope I've helped you.
I hope you've undertand the image.
Answer:
Range= $144,000
Step-by-step explanation:
The least amount for each car is 22,000 and the highest is 25,000
so assuming the dealer sells all of them the lowest price, the revenue would be, $1,056,000 (that would be the lowest revenue) and assuming he sells all the cars at the highest price, the dealer will get a revenue of $1,200,000. So the lowest revenue is 1,056,000 and the highest revenue is 1,200,000. So to find the range subtract the highest revenue by the lowest and you’ll get $144,000.
The correct answer is letter C