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JulijaS [17]
3 years ago
15

Please help me step by step thanks

Mathematics
1 answer:
Gemiola [76]3 years ago
7 0
Left:
180-53 = (8x-9)
127+9 = 8x
136 = 8x
x = 17
Right:
(15x+29) = (26x-4)
29+4 = 26x-15x
33 = 11x
x = 3
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Plz help will mark brainliest
DENIUS [597]

Answer:

-x^1} \\\\\\Hope that helps!

Step-by-step explanation:

8 0
2 years ago
Find the distance between the points (11, 4) and (10, 5).​
alexdok [17]

Answer:

square root of 2 or if needed simplified, 1.414213 to the nearest millionth.

Step-by-step explanation:

Start with the equation d= square root of (11-10)^2+(4-5)^2 where that is simplified to square root of (1)^2+(-1)^2 to square root of 1+1 to your final answer, square root of 2. Also simplified to 1.414213.

6 0
3 years ago
What is the value of P for the following triangular prism?
Zolol [24]
Pretty sure its 36 (not sure) i keep getting 36.6 cm
3 0
2 years ago
A circular mirror is surrounded by a metal frame. The radius of the mirror is 2x. The side length of the metal frame is 12x. Wha
meriva

Answer:

Area\ of\ th\e metal\ frame = 65.5x^{2}\ (unit)^{2}

Step-by-step explanation:

Assuming that the metal frame is a square metal frame because the length of the side of the metal frame is given.

Given:

Radius of the mirror = 2x unit

Side length of the square metal frame = 12x unit

We need to find the area of the metal frame.

Solution:

First we find the area of the circular mirror, using area formula of the circle.

A_{c} = \pi r^{2}

Where, r = Radius of the object.

Substitute r = 2x in above equation.

A_{c} = \pi (5x)^{2}

A_{c} = \pi (25x^{2})

A_{c} = 25\pi x^{2}\ (unit)^{2}

Now, we find the area the square, using area formula of the square.

A_{S} = (Side\ length)^{2}

A_{S} = (12x)^{2}

A_{S} = 144x^{2}\ (unit)^2}

So, the area of the square metal frame is given as

A_{f}=A_{s}-A_{c}

A_{f}=144x^{2}-25\pi x^{2}

A_{f}=(144-25\pi) x^{2}

A_{f}=(144-25\times 3.14) x^{2}

A_{f}=(144-78.5) x^{2}

A_{f}=65.5 x^{2}\ (unit)^{2}

Therefore, the area of the metal frame is 65.5x^{2}\ (unit)^{2}.

5 0
2 years ago
Two similar cylinders have surface areas of 24pi cm^2 and 54pi cm^2. The volume of the smaller cylinder is 16pi cm^2. What is th
ankoles [38]

Answer:

Step-by-step explanation:

i need this too

6 0
3 years ago
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