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Gnoma [55]
3 years ago
9

what is the area of a regular pentagon with sides of length 13 and an apothem of length 8.95, in square units

Mathematics
1 answer:
Assoli18 [71]3 years ago
3 0
The area is 290.760680699535.
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Use the dchnition of similarity to solve the following problem.
sveta [45]

Answer:

  1063 ft

Step-by-step explanation:

For shadow problems, we assume the sun's rays are parallel, so the triangles formed are similar. That means the ratio of height to shadow length is the same for each object.

  h/(580 ft) = (5.5 ft)/(3 ft)

  h = (5.5 ft)(580/3) ≈ 1063 ft

The height of the monument is about 1063 feet.

8 0
2 years ago
Assume that trees are subjected to different levels of carbon dioxide atmosphere with 7% of the trees in a minimal growth condit
taurus [48]

Answer: The mean and standard deviation are 567.2 and 89.88 resp.

Step-by-step explanation:

Since we have given that

For 370 parts per million = 7% = 0.07

For 440 parts per million = 10% = 0.10

For 550 parts per million = 49% = 0.49

For 670 parts per million = 34% = 0.34

So, Mean of the carbon dioxide atmosphere for these trees would be

E[x]=370\times 0.07+440\times 0.1+550\times 0.49+670\times 0.34=567.2

And

E[x^2]=370^2\times 0.07+440^2\times 0.1+550^2\times 0.49+670^2\times 0.34=329794

So, Variance would be

Var\ x=E[x^2]-E[x]^2=329794-567.2^2=8078.16

So, the standard deviation would be

\sigma=\sqrt{8078.16}=89.88

Hence, the mean and standard deviation are 567.2 and 89.88 resp.

3 0
3 years ago
How do you graph this ​
Trava [24]

Answer:

=6

Step-by-step explanation:

hat is this passage mostly about?

Click for the passage, "Studies in Ice."

A. Studying nature

B. Storing and moving ice safely

C. Powering drills with the sun

D. Saving messages in ice

3 0
2 years ago
If the area around the vegetable garden is of uniform width (labeled with x) and the dimensions of the vegetable garden is 45 fe
Nady [450]
Area of Rectangle = Width × Length

Vegetable Garden
Width = 20
Length = 45
Area of Vegetable Garden = 20×45=900 Sq ft

Area of Entire Garden = Width × Length
Width = 20 + 2x
Length = 45 + 2x
Area = (20 + 2x)(45 + 2x)
(2x + 20)(2x + 45)
4x^2 + 90x + 45x + 900
Area of Entire Garden = 4x^2 + 135x + 900

Area of Flower Garden = Area of Entire Garden - Area of Vegetable Garden

(4x^2 + 135x + 900) - (20 × 45)
4x^2 + 135x + 900 - 900
Area of Flower Garden = 4x^2 + 135x

7 0
2 years ago
Select all that apply<br><br>which of the following represent the rule y=x+2?​
padilas [110]

Answer:

The first one and the second one.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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