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Mathematics

2 answers:

Kitty [74]3 years ago

6 0

Answer:

thank yoy so much for these free points, and I hope you have the best day because you deserve to have a really good day

Step-by-step explanation:

Please mark me as brainliest!

riadik2000 [5.3K]3 years ago

5 0

Answer:

awwww tyyy!! that was rlly kind of you!! :3 have a nice day <3 (also sorry if I'm too late XD)

Step-by-step explanation:

tyyy again!!

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What contribution to geometry is attributed to the work of René Descartes?

tresset_1 [31]

René Descartes provided the first systematic link between Euclidean geometry and algebra.

<h3>What is Geometry?</h3>

This branch of mathematics involves the study of object shape, their spatial relationship and that of their surrounding space.

René Descartes is referred to as the father of analytic geometry due to him establishing the relationship between Euclidean geometry and algebra.

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2 years ago

Air pressure may be represented as a function of height (in meters) above the

denis-greek [22]

Answer: OPTION C.

Step-by-step explanation:

<h3> The complete exercise is: "Air pressure may be represented as a function of height (in meters) above the surface of the Earth, as shown below:</h3><h3> $P(h) =P_0e^{-0.00012h}$ </h3><h3> In this function $P_o$ is the air pressure at the surface of the earth, and $h$ is the height above the surface of the Earth, measured in meters. At what height will the air pressure equal 50% of the air pressure at the surface of the Earth"</h3><h3></h3>

Given the following function:

$P(h) =P_0e^{-0.00012h}$

In order to calculate at what height the air pressure will be equal 50% of the air pressure at the surface of the Earth, you can follow these steps:

1. You need to substitute $P(h)=0.5P_o$ into the function:

$0.5P_o=P_0e^{-0.00012h}$

2. Finally, you must solve for $h$ .

Remember the following property of logarithms:

$ln(b)^a=a*ln(b)\\\\ln(e)=1$

Then, you get this result:

$0.5P_o=\frac{P_o}{e^{0.00012h}}\\\\(0.5P_o)(e^{0.00012h})=P_o\\\\e^{0.00012h}=\frac{P_o}{0.5P_o}\\\\ln(e)^{0.00012h}=ln(2)\\\\0.00012h*1=ln(2)\\\\h=\frac{ln(2)}{0.00012}\\\\h=5576.2$