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3 years ago

What is the index when the expression x^2/3 is rewritten as a radical expression?

Mathematics

1 answer:

yan [13]3 years ago

3 0

x^2/3 = ∛x^2

hope it helps

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Reflect shape A in the line x=-1

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Step-by-step explanation:

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Use any order, any grouping to write an equivalent expression: 3(2x) + 4y(5) + (4 x 2 x z)

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Answer:

We conclude that the equivalent expression is:

$3\left(2x\right)+4y\left(5\right)+\left(4\times \:2z\right)=6x+20y+8z$

Step-by-step explanation:

Given the expression

$3\left(2x\right)+4y\left(5\right)+\left(4\times \:2z\right)$

Remove parentheses: (a) = a

$=3\times \:2x+4\times \:5y+4\times \:2z$

Multiply the numbers: 3 × 2 = 6

$=6x+4\times \:5y+4\times \:2z$

Multiply the numbers: 4 × 5 = 20

$=6x+20y+4\times \:2z$

Multiply the numbers: 4 × 2 = 8

$=6x+20y+8z$

Thus, we conclude that the equivalent expression is:

$3\left(2x\right)+4y\left(5\right)+\left(4\times \:2z\right)=6x+20y+8z$

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A: 1/5 units B: 4 units C: 15.5 units D: 24 units E: 18 units With screenshot

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Suppose the force acting on a column that helps to support a building is a normally distributed random variable X with mean valu

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Answer:

(1) 0.4207

(2) 0.7799

Step-by-step explanation:

Given,

Mean value,

$\mu = 15.0$

Standard deviation,

$\sigma = 1.25$

(1) P(X ≥ 17.5) = 1 - P( X ≤ 17.5)

$= 1- P(\frac{x-\mu}{\sigma} \leq \frac{17.5-\mu}{\sigma})$

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$=1-P(z\leq 2)$

$=1- 0.5793$ ( By using z-score table )

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$=P(z\leq \frac{18 - 15}{1.25}) - P(z\leq \frac{14 - 15}{1.25})$

$=P(z\leq \frac{3}{1.25}) - P(z\leq -\frac{1}{1.25})$

$=P(z\leq 2.4) - P(z\leq -0.8)$

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