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larisa86 [58]
3 years ago
14

Write an equation in point-slope form for the perpendicular bisector of the segment with endpoints m(-1,-3) and n(7,1)

Mathematics
1 answer:
AlekseyPX3 years ago
5 0
To find the perpendicular bisector, you have to find the midpoint of mn
which is

(  \frac{-1 -7}{2} ,  \frac{-3 -1}{2} ) = (-4, -2)  <-- midpoint of mn

next you find the slope of mn which is
 
\frac{-3 -1}{-1 -7} =  \frac{-4}{-8} = 1/2 <- this is the slope

to find the perpendicular slope, you take the negative recipricol which is

-2

so now we know the perpendicular bisector line has a slope of -2 and passes through (-4, -2)

so 

y-(-2) = -2(x-(-4))
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Write your answer as a decimal or whole number.<br><br> ___% of $75=$42
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\frac{x}{100} · \frac{42}{75}

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Simplify: 5x + 4x2 + 10 + 2x2 + 2x – 6+2 - 1.
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A baseball glove is on sale for $34.00, which is 15% off of its original price. What was the original price of the baseball glov
Y_Kistochka [10]

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3 0
3 years ago
the straight line L, has equation y=3x-4 The straight line 1, in perpendicular to L, and passes through the point (9.5) Find an
kari74 [83]

Given:

The equation of given line is

y=3x-4

A line is perpendicular to the given line and passes through the point (9,5).

To find:

The equation of the perpendicular line.

Solution:

We have,

y=3x-4

On comparing this equation with slope intercept form y=mx+b, we get

m=3

It means, the slope of the given line is 3.

The product of slopes of two perpendicular lines is -1.

m\times m_1=-1

3\times m_1=-1

m_1=-\dfrac{1}{3}

Point slope form of a line is

y-y_1=m(x-x_1)

Where, m is the slope.

The slope of perpendicular line is -\dfrac{1}{3} and it passes through the point (9,5). So the equation of the line is

y-5=-\dfrac{1}{3}(x-9)

y-5=-\dfrac{1}{3}(x)-\dfrac{1}{3}(-9)

y-5=-\dfrac{1}{3}x+3

Adding 5 on both sides, we get

y-5+5=-\dfrac{1}{3}x+3+5

y=-\dfrac{1}{3}x+8

Therefore, the equation of required line is y=-\dfrac{1}{3}x+8.

5 0
2 years ago
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