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Artemon [7]
4 years ago
14

Can someone help me with this question please?

Mathematics
1 answer:
Paladinen [302]4 years ago
7 0
60 movies ------ 100%
9 movies -------- x%
__________________
60*x=9*100%
60x=900%   |:60
x=15%

The answer is 15%
:)
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The troposphere extends from the earths surface to a height of 6-12 miles depending on the location and the season. If a plane i
Vika [28.1K]

Answer:

2.8

Step-by-step explanation:

8.6 - 5.8

6 0
3 years ago
The length of a rectangle is x feet. Its width is (x-7) feet. Draw and label a rectangle to represent this situation. Then write
a_sh-v [17]

Answer:

Perimeter of rectangle:

(4x - 14)\text{ feet}            

Step-by-step explanation:

We are given the following in the question:

Length of rectangle:

x\text{ feet}

Width of rectangle:

(x-7)\text{ feet}

Perimeter of rectangle:

2\times \text{(Length + Width)}

Expressions to calculate perimeter

1. ~2((x) + (x - 7))\text{ feet}\\2.~2(2x-7)\text{ feet}\\3.~ 4x-14\text{ feet}

The attached image shows the image of the rectangle.

3 0
3 years ago
Write the slope intersect form of the equation. <br><br> Through (8,1) perpendicular to y =1/2x +2
dolphi86 [110]

Answer:

Step-by-step explanation:

y= -(1/2)x - 5

6 0
2 years ago
Math:
Dahasolnce [82]

Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

\sqrt{3}\cdot \csc x - 2 = 0

\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

\sqrt{3} - 2\cdot \sin x = 0

\sin x = \frac{\sqrt{3}}{2}

x = \sin^{-1} \frac{\sqrt{3}}{2}

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

2\cdot \cos x = -1

\cos x = -\frac{1}{2}

x = \cos^{-1} \left(-\frac{1}{2} \right)

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

7 0
3 years ago
A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 ce
julsineya [31]

Answer:

The proportion of students whose height are lower than Darnell's height is 71.57%

Step-by-step explanation:

The complete question is:

A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 centimeters. Darnel is a middle school student with a height of 161.4cm.

What proportion of proportion of students height are lower than Darnell's height.

Answer:

We first calculate the z-score corresponding to Darnell's height using:

Z=\frac{X-\mu}{\sigma}

We substitute x=161.4 , \mu=150, and \sigma=20 to get:

Z=\frac{161.4-150}{20} \\Z=0.57

From the normal distribution table, we read 0.5 under 7.

The corresponding area is 0.7157

Therefore the proportion of students whose height are lower than Darnell's height is 71.57%

8 0
3 years ago
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