2 years ago

What is the answer to the problem 3(2x-5)-4(x-3)=7

Mathematics

1 answer:

il63 [147K]2 years ago

3 0

Disitribute the 3 to the first parenthesis:

$3(2x-5) = 6x-15$

Distribute the 4 to the second parenthesis:

$4(x-3)=4x-12$

So, the equation becomes

$6x-15-4x+12=7 \iff 2x=10 \iff x = \dfrac{10}{2} = 5$

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Read 2 more answers

Find the illegal values of c in the multiplication statement c^2-3c-10/c^2+5c-14 times c^2-c-2/c^2-2c-15

Citrus2011 [14]

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