Question

What is the answer to the problem 3(2x-5)-4(x-3)=7

Answer 1

Disitribute the 3 to the first parenthesis:

$3(2x-5) = 6x-15$

Distribute the 4 to the second parenthesis:

$4(x-3)=4x-12$

So, the equation becomes

$6x-15-4x+12=7 \iff 2x=10 \iff x = \dfrac{10}{2} = 5$