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Sonbull [250]
3 years ago
13

Joseph saved his money to buy your table computer he purchased a computer with those cuz she had he gave the sale clark 4 hundre

d dollar bill 23 ten dollor bill 46 dimes and 19 pennies how much money did joseph give the sale clek
Mathematics
1 answer:
andre [41]3 years ago
4 0

Hello! We know that we have $400. So 23 ten dollar bills is equal to $230. How? We multiply 23 x 10 and get $230. Then, we have 46 dimes. A dime is worth 10 cents so we multiply 46 x 10 which equals $4.60. And of course we have the 19 cents. Now we add. 400 + 230 + 4.60 + 19 = $653.6.

Hope this Helps!

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An object moves along a coordinate axis so that its position at time t is given by s(t)=t3. Estimate its instantaneous velocity
Mademuasel [1]

If the position at time <em>t</em> is

<em>s(t)</em> = (1 m/s³) <em>t</em> ³

then the average velocity over <em>t</em> = 2 s and <em>t</em> = 2.001 s is

<em>v</em> (ave) = (<em>s</em> (2.001 s) - <em>s</em> (2 s)) / (2.001 s - 2 s)

<em>v</em> (ave) = ((1 m/s³) (2.001 s)³ - (1 m/s³) (2 s)³) / (2.001 s - 2 s)

<em>v</em> (ave) ≈ (8.01201 m - 8 m) / (0.001 s)

<em>v</em> (ave) ≈ 12.006 m/s

6 0
2 years ago
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MrRa [10]

Answer:

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Step-by-step explanation:

The centroid of a triangle is the intersection of the three medians of the triangle (each median connecting a vertex with the midpoint of the opposite side).

7 0
3 years ago
Please need help today it’s due today
il63 [147K]

Answer:

i think it is c(3)

Step-by-step explanation:

3 0
2 years ago
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Find square root of 144 by factorisation method​
Nady [450]

\huge \boxed{\mathbb{QUESTION} \downarrow}

  • Find square root of 144 by factorisation method.

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

We can find the square root of 144 using the factorisation method. In this method, you need to factorise 144 first. Then, you'll get your answer in the form of prime factors. In this case, it's ⇨ 2 × 2 × 2 × 2 × 3 × 3.

__________________

To find the square root using factorisation, we need to group the same number in pairs. That is, 2 × 2 × 2 × 2 × 3 × 3 by grouping same numbers in pairs will become ⇨ (2, 2), (2, 2), (3, 3).

__________________

Now, you should take only 1 of the number from these groups. So, (2, 2), (2, 2), (3, 3) will change to ⇨ 2 × 2 × 3.

__________________

Finally, just multiply this set of numbers to find the square root of 144. 2 × 2 × 3 = 4 × 3 = \large\boxed{\underline{\bf \: 12}} ⇨ square root of 144.

__________________

  • The square root of 144 is <em><u>1</u></em><em><u>2</u></em><em><u>.</u></em>

8 0
2 years ago
Evaluate the series
dalvyx [7]

Answer:

the value of the series;

\sum_{k=1}^{6}(25-k^2) = 59

C) 59

Step-by-step explanation:

Recall that;

\sum_{1}^{n}a_n = a_1+a_2+...+a_n\\

Therefore, we can evaluate the series;

\sum_{k=1}^{6}(25-k^2)

by summing the values of the series within that interval.

the values of the series are evaluated by substituting the corresponding values of k into the equation.

\sum_{k=1}^{6}(25-k^2) =(25-1^2)+(25-2^2)+(25-3^2)+(25-4^2)+(25-5^2)+(25-6^2)\\\sum_{k=1}^{6}(25-k^2) =(25-1)+(25-4)+(25-9)+(25-16)+(25-25)+(25-36)\\\sum_{k=1}^{6}(25-k^2) =24+21+16+9+0+(-11)\\\sum_{k=1}^{6}(25-k^2) = 59\\

So, the value of the series;

\sum_{k=1}^{6}(25-k^2) = 59

6 0
3 years ago
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