Vondra and Mei are 6 meters apart.
<u>Step-by-step explanation:</u>
<u>From the given information, It can be known that</u> :
- Vondra is directly south of Mei ⇒ which forms the height of the triangle.
- Vondra is directly west of Yoshi ⇒ which forms the base of the triangle.
The distance between Vondra and Yoshi are 8 meters which is the base of the triangle. (Base= 8).
The distance between Yoshi and Mei are 10 meters which is the hypotenuse of the triangle. (hypotenuse= 10).
<u>To find the distance between Vondra and Mei which is the height of the triangle :</u>
From the Pythagorean triplets (3,4,5),
It is determined that the multiples of (3,4,5) = (6,8,10) forms the triangle in this particular case.
Therefore, the height is 6 meters. That is, the distance between Vondra and Mei is 6 meters.
Answer:
e.) (x+1)2-308=x
Step-by-step explanation:
Answer:
4 in
Step-by-step explanation:
Answer:
13.5 minutes
Step-by-step explanation:

Cross multiply
3 × 576 = 128x
3 × 576 = 1,728
1,728 = 128x
1,728 ÷ 128 = x
13.5 = x
9514 1404 393
Answer:
671 feet
Step-by-step explanation:
There are a couple of ways to figure this. One is to use a sort of shortcut equation to find the distance traveled (d) by an object when subject to some initial velocity (v) and acceleration (a). Here the acceleration due to gravity is -32 ft/s².
v² = 2ad
d = v²/(2a) = (192 ft/s)^2/(2·32 ft/s²) = 576 ft
This height is in addition to the starting height of 95 ft, so the arrow's maximum height is ...
max height = 95 ft + 576 ft = 671 ft
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Another way to work this problem is to start with the equation for ballistic motion. Filling in the given initial velocity and height, we have ...
h(t) = -16t^2 +192t +95
The time the arrow reaches the maximum height is the time representing the axis of symmetry of the parabola:
t = -(192)/(2(-16)) = 6
Then the maximum height is ...
h(6) = -16·6^2 +192·6 +95 = 671
The maximum height is 671 feet.
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<em>Additional comment</em>
For the standard-form quadratic ...
y = ax^2 +bx +c
The axis of symmetry is ...
x = -b/(2a)