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masya89 [10]
3 years ago
8

. . What needs to be corrected in the following construction for copying ∠ABC with point D as the vertex?.

Mathematics
2 answers:
sladkih [1.3K]3 years ago
5 0
The correct answer to this question is "The third arc should cross the third arc." Line DM is another line in which the third arc is present - which is also very similar to line BC. It will be the same as the point on line AB, where the third and second arc meet.
SIZIF [17.4K]3 years ago
4 0
From my research, the image below belongs to the question. From what is seen in the image, there are 2 arcs already drawn with respect to the new vertex. The third arc corresponds to the point where the line DM is made. This line is similar to line BC. So at the point where the second and third arcs would meet, it would be a point similar to a point on line AB.

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Linear equations... HELP!
fgiga [73]
The answer is m = 250 - 25w.
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In slope-intercept form, m is the slope and b is y-intercept.
In m = 250 - 25w, the y-intercept is 250 and the slope is -25.
This matches the graph.
Y-intercept is where a line crosses the y-axis, which is 250 in this case.
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4 0
3 years ago
What is the probability that a point chosen at random in the regular hexagon lies in the shaded region? A 1/3 B 2/5 C 1/2 D 2/3
kondaur [170]
Answer: option A) 1/3

Justification:

1) The probability that a point chosen at random <span>in the regular hexagon lies in the shaded region is equal to:

  area of the shaded region
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2) The hexagon is formed by 6 equal triangles and the shaded area is formed by 2 of those triangles.

3) Therefor,naming x the area of one triangle, the the above fraction is equal to:

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  area of six triangles            6x

And that is the answer: 1/3
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3 years ago
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Step-by-step explanation:

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LiRa [457]

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What we are looking for are points of discontinuity. Think of it as when you remove your pencil from the paper.

From left to right, the graph stops at x = -3. So anything less than -3 is in the domain. Next, the graph starts up again at x =-1 after an asymptote (the vertical dashed lines). This piece goes to x = 4. So our domain is from -1 to 4.

Lastly, there's a jump from 4 to 5 and the graph goes on again. After 5, we take all the stuff more than it. So x > 5 is in the domain.

So x < -3, - 1 < x < 4, and x > 5 appears to be our domain. However, end points needed to be checked to see if we include them or not. Again we go left to right.

At x = -3 there is a filled (or closed) circle and that means we include -3.

At x = -1 there is an asymptote. Asymptotes are things you get close to but don't get to. (Think of it as the "I'm Not Touching" game you play on car trips.) So we exclude -1.

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Now we refine our domain for the endpoints.

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Our domain is (-∞, -3] ∪(-1,4) ∪ [5,∞).

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