3 years ago

How do you get the number 50 with the numbers 2,3,6,8 with using all numbers and only using them once.

Mathematics

1 answer:

AleksandrR [38]3 years ago

5 0

Answer:

Impossible

Step-by-step explanation:

You can write 50 as

$=(6 \times 8)+2$

But 3 is not used in this representation

But it is mentioned in the question that all number must be used at least once

Therefore it is not possible

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Step-by-step explanation:

Given:

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$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

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