A line that is perpendicular to y=-3x-10 passing through the point (6,8)
1 answer:
Answer: y = -1/3x + 10
Step-by-step explanation:
To make it perpendicular change the reciprocals
So instead of 3x it'll be -1/3x and so it passes through the given points
plug the points
8 = -1/3(6) + b
8 = -2 + b
add 2 to both sides
10 = b
so the equation of a line thats perpendicular to y=-3x-10 and passes through
points (6,8) is
y = -1/3x + 10
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