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erastovalidia [21]
3 years ago
14

What composite number is greater than 38 but less than 50? A.41 B.47 C.49 D.55

Mathematics
2 answers:
N76 [4]3 years ago
8 0
The awnser would be c
IrinaK [193]3 years ago
5 0

Answer:

I just took the test i got c


Step-by-step explanation:


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Rob cut a 15-foot wire into 8 equal pieces. about how long is each piece
Archy [21]
For this answer it is really going to depend on what you are rounding to. You need to start by dividing 15 by 8. This gives you 1.875 feet. If you are wanting your answer to the nearest hundreth of a foot your answer would be 1.88 feet.
If you are wanting your answer to the nearest tenth of a foot your answer would be 1.9 feet. And if you are wanting your answer to the nearest food your answer would be 2 feet.
7 0
3 years ago
Im putting all the questions in one to make it easier
Rufina [12.5K]

I'll focus on problem 19 and problem 22

============================================================

Problem 19

Answers:

  • x = 87
  • x+15 = 102

-------------------------------

Explanation:

The horizontal lines are parallel. Note the arrow markers along the interior portion of the lines. These similar markers tell us how the lines pair up to be parallel to one another.

Since the horizontal lines are parallel, this means the angles in question are congruent. They are corresponding angles.

x+15 = 102

x = 102-15

x = 87

Which leads to

x+15 = 87+15 = 102

============================================================

Problem 22

Answer: y = 27

-------------------------------

Explanation:

We have a pair of alternate exterior angles. They are congruent due to the parallel lines.

Let's solve for y.

7y-55 = 3y+53

7y - 3y = 53+55

4y = 108

y = 108/4

y = 27

5 0
3 years ago
I need help. it’s due tonight.thank you
masha68 [24]

Answer:28

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Can someone plz explain I would appreciate it
mafiozo [28]

Answer:

Angle of depression

Step-by-step explanation:

4 0
3 years ago
Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f
castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean (\mu) = 115 \times 20

= 2300

Standard deviation = 20 \times \sqrt{115}

Standard deviation (SD) = 214.4761

TO find:

a) P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})

P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})

P(x > 3500)= P(Z > \dfrac{1200}{214.4761})

P(x > 3500)= P(Z >5.595)

From the Z-table, since 5.595 is > 3.999

P(x > 3500)=1-0.9999

P(x > 3500) = 0.0001

b)

Here, the replacement time for the mean (\mu) = \dfrac{0+0.5}{2}

= 0.25

Replacement time for the Standard deviation \sigma = \dfrac{0.5-0}{\sqrt{12}}

\sigma = 0.1443

For 115 component, the mean time = (115 × 20)+(114×0.25)

= 2300 + 28.5

= 2328.5

Standard deviation = \sqrt{(115\times 20^2) +(114\times (0.1443)^2)}

= \sqrt{(115\times 400) +(114\times 0.02082249}

= \sqrt{(46000) +2.37376386}

= \sqrt{(46000) +(2.37376386)}

= \sqrt{46002.374}

= 214.482

Now; the required probability:

P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})

P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})

P(x > 4125) = P(Z >8.376)

P(x > 4125) =1-  P(Z

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

P(x > 4125) = 0.0001

7 0
2 years ago
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