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3 years ago

5

There are 15 students in the class and 8 are boys. What is the ratio of girls to students in the room?

1 answer:

cricket20 [7]3 years ago

8 0

Answer:

7/15

Step-by-step explanation:

hope this helps?:)

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What is the vertex of f(x) = |x + 8| – 3?

Arte-miy333 [17]

Answer:

(-8,-3)

Step-by-step explanation:

This question is similar to the vertex form of a quadratic equation, so you can think of this equation like f(x) = (x-h)+k. Using this equation, you can determine the vertex (h,k) of |x+8|-3, which is (-8,-3).

5 0

3 years ago

i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.

Natali [406]

Answer:

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = -5\sqrt 2$

Step-by-step explanation:

Given

$N = (-7,-1)$ --- terminal side of $\varnothing$

Required

Determine the values of trigonometric functions of $\varnothing$ .

For $\varnothing$ , the trigonometry ratios are:

$sin\ \varnothing = \frac{y}{r}$ $cos\ \varnothing = \frac{x}{r}$ $tan\ \varnothing = \frac{y}{x}$

$cot\ \varnothing = \frac{x}{y}$ $sec\ \varnothing = \frac{r}{x}$ $csc\ \varnothing = \frac{r}{y}$

Where:

$r^2 = x^2 + y^2$

$r = \sqrt{x^2 + y^2$

In $N = (-7,-1)$

$x = -7$ and $y = -1$

So:

$r = \sqrt{(-7)^2 + (-1)^2$

$r = \sqrt{50$

$r = \sqrt{25 * 2$

$r = \sqrt{25} * \sqrt 2$

$r = 5 * \sqrt 2$

$r = 5 \sqrt 2$

<u>Solving the trigonometry functions</u>

$sin\ \varnothing = \frac{y}{r}$

$sin\ \varnothing = \frac{-1}{5\sqrt 2}$

Rationalize:

$sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$sin\ \varnothing = \frac{-\sqrt 2}{5*2}$

$sin\ \varnothing = \frac{-\sqrt 2}{10}$

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{x}{r}$

$cos\ \varnothing = \frac{-7}{5\sqrt 2}$

Rationalize

$cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}$

$cos\ \varnothing = \frac{-7\sqrt 2}{10}$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{y}{x}$

$tan\ \varnothing = \frac{-1}{-7}$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = \frac{x}{y}$

$cot\ \varnothing = \frac{-7}{-1}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{r}{x}$

$sec\ \varnothing = \frac{5\sqrt 2}{-7}$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = \frac{r}{y}$

$csc\ \varnothing = \frac{5\sqrt 2}{-1}$

$csc\ \varnothing = -5\sqrt 2$

3 0

3 years ago

In 3a + b - 12 Name The Coefficients.<br> A) 3<br> B )3 , 1 , 12<br> C) 3, 1<br> D) a , b

emmainna [20.7K]

Answer:

A) 3

Step-by-step explanation:

The coefficient is a number next to a variable so 3 would be the answer.

3 0

3 years ago

Read 2 more answers

How much would you pay for Light Oak wood floors at $2.76 per sqft for a room that is 14 X 16?

Alchen [17]

Answer:

$618.24

Step-by-step explanation:

The area of the room is 224. Then for each square feet is 2.76 do multiplying that you get the answer.

8 0

2 years ago

Pleae help me, will brianly

Licemer1 [7]

Answer:

A' (-3, -2)

B' (-3, -10)

C' (3, -10)

D' (3, -3)

Step-by-step explanation:

When reflecting over the y-axis, the x- coordinates don't change, rather only the position of the y-value is shifted. When moving the y-values, it is good to count how many spaces away the point is from the line , so it can be duplicated when you flip it.

Hope this Helps! :)

5 0

3 years ago

Read 2 more answers