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dybincka [34]
3 years ago
5

Not sure how to solve 2sinxcosx+cosx=0  Could you help?

Mathematics
1 answer:
kaheart [24]3 years ago
6 0
2sinxcosx+cosx=0\\\\cosx(2sinx+1)=0\iff cosx=0\ \vee\ 2sinx+1=0\\\\cosx=0\ \vee\ 2sinx=-1\ /:2\\\\cosx=0\ \vee\ sinx=-\frac{1}{2}\\\\x=\frac{\pi}{2}+k\pi\ \vee\ x=-\frac{\pi}{6}+2k\pi\ \vee\ x=\frac{7\pi}{6}+2k\pi\ to\ k\in\mathbb{Z}
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Which of the statements below is true for the following set of numbers?<br> 20, 5, 50, 95, 75, 60
lora16 [44]

Answer:

20 50 60 ..........

Step-by-step explanation:

205060

8 0
3 years ago
Suppose you and some friends are going to the movies. The amount of money you spend for tickets varies directly with the number
Aneli [31]
Money spent = number of people *  price of 1 ticket  (direst variation)
  28               = 4 *  price of a ticket

so price of one ticket = 28/4 =  7

Constant of variation is 7

we might write it as m = 7n
8 0
3 years ago
Read 2 more answers
1+4=5<br> 2+5=12<br> 3+6=21<br> 8+11=?
lilavasa [31]

well,

1 + 4 = 1 x (4 +1) = 1 x 5 = 5

2 + 5 = 2 x (5 + 1) = 2 x 6 = 12

3 + 6 = 3 x (6 + 1) = 3 x 7 = 21

Therefore we can find the missing number as;

8 + 11 = 8 x (11 + 1) = 8 x 12 = 96

<span>Answer = 96</span>

4 0
3 years ago
Determine whether the relation R on the set of all Web pages is reflexive, symmetric, antisymmetric, and/or transitive, where (a
xxMikexx [17]

Answer:

a) R is reflexive, R is not symmetric, R is not anti-symmetric, R is transitive.

b) R is reflexive, R is symmetric, R is not anti-symmetric, R is not transitive.

c) R is not reflexive, R is symmetric, R is not anti-symmetric, R is not transitive.

Step-by-step explanation:

a)

(a, b) ∈ R if and only if everyone who has visited Web page a has also visited Web page b.

Obviously R <em>is reflexive</em> (aRa)

Everyone who has visited Web page a has also visited Web page a

R <em>is not symmetric</em> (aRb does not imply bRa)

If everyone who has visited Web page a has also visited Web page b does not mean that everyone who has visited Web page b has also visited Web page a

R <em>is not anti-symmetric</em> (aRb and bRa does not imply a=b)

If everyone who has visited Web page a has also visited Web page b and everyone who has visited Web page b has also visited Web page a does not mean the web pages are the same.

R <em>is transitive</em> (aRb and bRc implies aRc)

If everyone who has visited Web page a has also visited Web page b and everyone who has visited Web page b has also visited Web page c implies that everyone who has visited Web page a has also visited Web page c.

b)

(a, b) ∈ R if and only if there are no common links found on both Web page a and Web page b.

R is obviously <em>reflexive</em> (aRa)

R <em>is symmetric </em>(aRb implies bRa)

if there are no common links found on both Web page a and Web page b, then there are no common links found on both Web page b and Web page a.

R <em>is not anti-symmetric</em> (aRb and bRa does not imply a=b)

if there are no common links found on both Web page a and Web page b and there are no common links found on both Web page b and Web page a does not mean a and b are the same web page.

R <em>is not transitive</em> (aRb and bRc does not imply aRc)

Consider for example three web pages a, b and c such that a and c have a common link and b has no external links at all.

Then obviously (a,b)∈R and (b,c)∈R since b has no links, but (a,c)∉R because they have a common link.

c)

(a, b) ∈ R if and only if there is at least one common link on Web page a and Web page b

R <em>is not reflexive </em>

If the web page a does not have any link at all, then a is not related to a.

R <em>is symmetric </em>(aRb implies bRa)

if there is at least one common link found on Web page a and Web page b, then there is at least one common link found on Web page b and Web page a.

R <em>is not anti-symmetric</em> (aRb and bRa does not imply a=b)

if there is at least one common link found on Web page a and Web page b and there is at least one common link found on Web page b and Web page a does not mean the web pages are the same

R <em>is not transitive</em> (aRb and bRc does not imply aRc)

Consider for example three web pages a, b and c such that a has only two links L1 and L2, b has only two links L2 and L3   c has only two links L3 and L4.  

Then (a, b) ∈ R since a and b have the common link L2, (b, c) ∈ R for b and c have the common link L3, but a and c have no common links, therefore (a,c)∉R

5 0
4 years ago
5. Priya can bike 150 meters in 20 seconds. At
Andreas93 [3]

Answer:

400 seconds

Step-by-step explanation:

Divide 3000/150 = 20

20 x 20 seconds = 400 seconds

6 0
3 years ago
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