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dybincka [34]
3 years ago
5

Not sure how to solve 2sinxcosx+cosx=0  Could you help?

Mathematics
1 answer:
kaheart [24]3 years ago
6 0
2sinxcosx+cosx=0\\\\cosx(2sinx+1)=0\iff cosx=0\ \vee\ 2sinx+1=0\\\\cosx=0\ \vee\ 2sinx=-1\ /:2\\\\cosx=0\ \vee\ sinx=-\frac{1}{2}\\\\x=\frac{\pi}{2}+k\pi\ \vee\ x=-\frac{\pi}{6}+2k\pi\ \vee\ x=\frac{7\pi}{6}+2k\pi\ to\ k\in\mathbb{Z}
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system of equations means that we have a given number of equations with the same solutions.

If you only have tables, this means that you need to have one table for each equation:

For example, if you are working only with two variables, x and y, in those tables you can see the pints (x, y) that belong to each equation.

Now, a point (x, y) will be a solution of the system of equations only if it belongs to the data table for each equation

This would mean that if you graph those data sets, the graphs will intersect at the point (x, y) that belongs to all the tables of data.

another way may be using the data in the tables to construct the equations, but you said that you only want to use the tables, so this method can be discarded.

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Answer:

d = (-9/13)

Step-by-step explanation:

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